4

The following creates a triangle.

Q1. How can I add lengths such as 5cm, 6cm and xcm for each side.

Q2. How can I add a right angle sign to A?

 \item[b)]
      \begin{tikzpicture}
% Draw the triangle
        \draw[fill=gray!10]  (0, 0) coordinate (A) 
        -- (0,5) coordinate (C) 
        -- (6,0) coordinate (B) 
        -- (0, 0);

% Draw nodes
        \node at (A)[anchor=north] {A};
        \node at (B)[anchor=north] {B};
        \node at (C)[anchor=south] {C};
      \end{tikzpicture}

enter image description here

6

One option:

\documentclass{article}
\usepackage{tikz}

\begin{document}

      \begin{tikzpicture}
% Draw the triangle
        \draw[fill=gray!10]  (0, 0) coordinate (A) 
        -- node[left] {$3$\,cm} (0,5) coordinate (C) 
        -- node[above right] {$5$\,cm} (6,0) coordinate (B) 
        -- node[below] {$4$\,cm}  (0, 0);
       \draw (0,10pt) -- ++(10pt,0) -- ++(0,-10pt);
% Draw nodes
        \node at (A)[anchor=north] {$A$};
        \node at (B)[anchor=north] {$B$};
        \node at (C)[anchor=south] {$C$};
      \end{tikzpicture}

\end{document}

enter image description here

Using a brace decoration, you could add braces to the sides to indicate the lengths:

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{decorations.pathreplacing}

\begin{document}

      \begin{tikzpicture}
% Draw the triangle
        \draw[fill=gray!10]  (0, 0) coordinate (A) 
        -- (0,5) coordinate (C) 
        -- (6,0) coordinate (B) 
        -- (0, 0);
       \draw[decoration={brace,mirror,raise=2pt},decorate] 
         (A) -- node[below=4pt] {$4$\,cm} (B); 
       \draw[decoration={brace,mirror,raise=2pt},decorate] 
         (B) -- node[above=4pt,sloped] {$5$\,cm} (C); 
       \draw[decoration={brace,mirror,raise=2pt},decorate] 
         (C) -- node[left=4pt] {$3$\,cm} (A); 

       \draw (0,10pt) -- ++(10pt,0) -- ++(0,-10pt);
% Draw nodes
        \node at (A)[anchor=north] {$A$};
        \node at (B)[anchor=north] {$B$};
        \node at (C)[anchor=south] {$C$};
      \end{tikzpicture}

\end{document}

enter image description here

4
  • \draw (0,10pt) -- ++(10pt,0) -- ++(0,-10pt);draws an angle, but these coordinates, - and + doesn't make any sense to me. How do you decide these?
    – shin
    May 5 '14 at 22:07
  • @shin Those draw two sides of a square of side 10pt. The drawing begins at the point (0,10pt) then go 10pt to the right, and finally 10pt downwards. May 5 '14 at 22:09
  • @shin These indicate relative coordinates as opposed to absolute coordinates.
    – cslstr
    May 5 '14 at 22:17
  • @shin the ++ modifier adds the coordinates to the previous point and locate the origin in the given coordinate. From the PGF manual: You can add a single + sign in front of a coordinate or two of them as in +(1cm,0cm) or ++(0cm,2cm). Such coordinates are interpreted differently: The first form means “1cm upwards from the previous specified position” and the second means “2cm to the right of the previous specified position, making this the new specified position. May 5 '14 at 22:18

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