Why does the following code trigger the error ! Dimension too large. when compiling it with pdflatex, even though the dimension should only be 11in (which is below \maxdimen)?



\pgfkeys{/pgf/fpu=true, /pgf/fpu/output format=fixed}
\pgfmathparse{10in + 1in}
\node at ( 0, \y ) { y-position: \y };


Basically I want to be able to calculate node positions using PGF's FPU, due to the \maxdimen limitation. Expressions like sqrt(pow(10in, 2) + pow(12in, 2)) don't seem to be possible in TikZ, even tho the actual result is only ~15.6in.


The result is within TeX dimension limits but you use the value without a unit, 794.96.... is understood as centimeters and it becomes 22K+ pts. So add pt after the \y

\node at ( 0, \y pt ) { y-position: \y };

enter image description here

  • This seems to work, makes sense. Is the result of \pgfmathresult always implicitly converted to pt, even though inches are used in the calculation?
    – watain
    May 7 '14 at 8:35
  • 1
    @watain Yes, TeX and hence TikZ works with pt and internally things are always converted to pt.
    – percusse
    May 7 '14 at 8:36

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.