Arrow from brace to node

Question

I would like to draw an arrow from the tip of a curly bracket to a node, but if I do the following, an extra arrow point is drawn just above the tip of the brace.

\documentclass{article}
\usepackage{pgfplots}
\begin{document}
\usetikzlibrary{decorations.pathreplacing}
\begin{tikzpicture}
  \node (A) at (0,0) {Hello};
  \draw[decorate, decoration={brace, amplitude=10pt}] (2.2,-1.8) -- coordinate [left=10pt] (B) (2.2,-0.3) node {};
  \draw[-latex] (B) edge (A);
\end{tikzpicture}
\end{document}

It looks very strange and I have no idea how this extra arrow got there. If I switch the B and the A like \draw[-latex] (A) edge (B);, only one arrow is drawn, can anybody explain this and explain how to do the above correctly?

Answer 1

I think the problem involves the use of edge which creates a second construction after the main path is drawn. Since [-latex] applies to the entire command until the ;, you end up with 2 arrows. Replacing edge with a regular -- removes the problem:

\documentclass[tikz]{standalone}
\usetikzlibrary{decorations.pathreplacing}
\begin{document}

\begin{tikzpicture}
  \node (A) at (0,0) {Hello};
  \draw[decorate, decoration={brace, amplitude=10pt}] (2.2,-1.8) -- coordinate [left=10pt] (B) (2.2,-0.3) node {};
  \draw[-latex] (B) -- (A);
\end{tikzpicture}

\end{document}