# One line drawn longer than another line on the same Cartesian plane

Why are the two lines drawn to different lengths? The slanted line should be shortened a bit - maybe by 2ex - and the vertical line should be lengthened to obtain the same height that the slanted line obtains.

How do I get the equation for the slanted line on the opposite side? The place it is now makes it look like I am labeling the curve y=(3/2)x + 5/2.

If I want a little more of the graph above the x-axis to be drawn, what should I change in the code? ymax=25 instead of ymax=15?

\documentclass{amsart}
\usepackage{tikz}
\usepackage{pgfplots}
\pgfplotsset{compat=1.11}

\begin{document}

\begin{tikzpicture}
\begin{axis}[width=4in,axis equal image,clip=false,
axis lines=middle,
xmin=-15,xmax=15,
domain=-15:15, samples=101,
xlabel=$x$,ylabel=$y$,
ymin=-15,ymax=15,
restrict y to domain=-20:20,
enlargelimits={abs=1cm},
axis line style={latex-latex},
ticklabel style={font=\tiny,fill=white},
xtick={\empty},ytick={\empty}
]
\addplot[samples=251,domain=1.5:25] {(3*x^2+5*x)/(2*x-3)} node[above,pos=0.85]{$\scriptstyle{y}=\frac{3x^{2}+5x}{2x-3}$};
\addplot [dashed, latex-latex] {(3/2)*x+5/2} node [pos=0.15, anchor=south, font=\footnotesize, sloped] {$y=\frac{3}{2}x+\frac{5}{2}$};
\addplot [dashed, latex-latex] (1.5,x) node [pos=0.15, anchor=north, font=\footnotesize, sloped] {$x=\frac{3}{2}$};
\end{axis}
\end{tikzpicture}

\end{document}


• Something like node[below] instead of above? – percusse Sep 27 '14 at 13:47
• You can get the equation of the slanted line the way you want by changing anchor=south to anchor=north. – Sony Sep 27 '14 at 13:51

\documentclass{amsart}
\usepackage{tikz}
\usepackage{pgfplots}
\pgfplotsset{compat=1.11}

\begin{document}

\begin{tikzpicture}
\begin{axis}[width=4in,axis equal image,clip=false,
axis lines=middle,
xmin=-15,xmax=15,
samples=101,
xlabel=$x$,ylabel=$y$,
ymin=-15,ymax=15,
restrict y to domain=-20:25,
enlargelimits={abs=1cm},
axis line style={latex-latex},
ticklabel style={font=\tiny,fill=white},
xtick={\empty},ytick={\empty},
]
\addplot[samples=251,domain=1.5:15] {(3*x^2+5*x)/(2*x-3)} node[above right,anchor=south west,pos=0.95]{$\scriptstyle{y}=\frac{3x^{2}+5x}{2x-3}$};
\addplot [dashed, latex-latex,domain=-13:10] {(3/2)*x+5/2} node [pos=0.15, anchor=north, font=\footnotesize, sloped] {$y=\frac{3}{2}x+\frac{5}{2}$};
\addplot [dashed, latex-latex,domain=-17:17.5] (1.5,x) node [pos=0.15, anchor=north, font=\footnotesize, sloped] {$x=\frac{3}{2}$};
\end{axis}
\end{tikzpicture}

\end{document}


Some explanations:

You can add the proper domain to the dashed plots. For the slanted line, let us say we fix ,domain=-13:10. Then the maximum and minimum values of y are 17.5 and -17 respectively. Noe we fix theses values for y in the vertical dashed line as domain=-17:17.5 in the coordinate {1.5,x}.

To bring the label below for the slanted line change the anchor to anchor=north,.

To extend the upper curve you have to change the values in restrict y to domain=-20:25,. Change the ymax and xmax, ymin and xmin values accordingly so as to get the axis line length suitably. (Or change the value of abs=1cm in enlargelimits).