5

My MWE:

\documentclass[]{report}

\usepackage{amsmath}

    \begin{document}

    \begin{align}
    \dot{V} =&\, \frac{1}{\gamma_{2,1}}\sigma_{2,1} \dot{\sigma}_{2,1} + \frac{1}{\gamma_{2,2}}\sigma_{2,2} \dot{\sigma}_{2,2} + \frac{1}{\gamma_{2,3}}\sigma_{2,3} \dot{\sigma}_{2,3} \notag \\
     =& - \left [\sigma_{2,1}^2 \sin^2(x_1) + \sigma_{2,2}^2 x_2^2 + \sigma_{2,3}^2 u^2 + 2\sigma_{2,1}\sigma_{2,2}\sin(x_1)x_2 + 2 \sigma_{2,1}\sigma_{2,3}\sin(x_1)u \right. \notag \\
    & \left. + 2 \sigma_{2,2}\sigma_{2,3}x_2 u \vphantom{\sigma_{2,1}^2} \right ] \notag \\
    \end{align}

    \end{document}

The result:

enter image description here

What I want:

enter image description here

1
  • Insert \quad or \qquad after the final &
    – Thruston
    Oct 24, 2014 at 15:23

1 Answer 1

4

Use & \phantom{{}= - \bigl[}. Also, you should use &= instead of =&. Further, use \bigl[ and \bigr] instead of \left[ and right]. This doesn't need to be balanced like \left.. Also the \\ in the last line shouldn't be used. In the last line, use {}+{} so that the spacing around + is correct.

\documentclass[]{report}

\usepackage{amsmath}

\begin{document}

\begin{align}
\dot{V} &= \frac{1}{\gamma_{2,1}}\sigma_{2,1} \dot{σ}_{2,1} + \frac{1}{\gamma_{2,2}}\sigma_{2,2} \dot{σ}_{2,2} + \frac{1}{\gamma_{2,3}}\sigma_{2,3} \dot{σ}_{2,3} \notag \\
 &= {}-{} \bigl[\sigma_{2,1}^2 \sin^2(x_1) + \sigma_{2,2}^2 x_2^2 + \sigma_{2,3}^2 u^2 + 2\sigma_{2,1}\sigma_{2,2}\sin(x_1)x_2 + 2 \sigma_{2,1}\sigma_{2,3}\sin(x_1)u  \notag \\
& \phantom{{}= - \bigl[} {}+{} 2 \sigma_{2,2}\sigma_{2,3}x_2 u \vphantom{\sigma_{2,1}^2} \bigr] \notag   %% no \\ here
\end{align}

\end{document}

enter image description here

Here is another version with shorter second line as recommended by egreg.

\documentclass[]{report}

\usepackage{amsmath}

\begin{document}

\begin{align}
\dot{V} &= \frac{1}{\gamma_{2,1}}\sigma_{2,1} \dot{σ}_{2,1} + \frac{1}{\gamma_{2,2}}\sigma_{2,2} \dot{σ}_{2,2} + \frac{1}{\gamma_{2,3}}\sigma_{2,3} \dot{σ}_{2,3} \notag \\
 &= {}-{} \bigl[\sigma_{2,1}^2 \sin^2(x_1) + \sigma_{2,2}^2 x_2^2 + \sigma_{2,3}^2 u^2 + 2\sigma_{2,1}\sigma_{2,2}\sin(x_1)x_2  \notag \\
& \phantom{{}= - \bigl[} {}+{}  2 \sigma_{2,1}\sigma_{2,3}\sin(x_1)u + 2 \sigma_{2,2}\sigma_{2,3}x_2 u \vphantom{\sigma_{2,1}^2} \bigr] \notag   %% no \\ here
\end{align}

\end{document}

enter image description here

8
  • The last line + is a unary operator, I would convert it to a binary operator; even if there's nothing before on that line, there is in the expression.
    – Manuel
    Oct 24, 2014 at 15:37
  • @Manuel I missed that one. Thanks for noting and corrected.
    – user11232
    Oct 24, 2014 at 15:40
  • 1
    not sure why you've used a \phantom at the beginning of the third line when \qquad would probably do as well; if it's really meant to line up the plus just inside the opening bracket, then repeating the string from the previous line, as \phantom{{}= - \bigl[}, would be more appropriate. Oct 24, 2014 at 15:47
  • As barbara says, I think in case you are not trying to align anything, then \quad or \qquad is enough. But that's just a “matter of taste” :)
    – Manuel
    Oct 24, 2014 at 15:54
  • what i think has happened here is that the change to get a unary minus in the second line was not back-edited into the code; that's why the extra space when you use the code i quoted in my comment. if that's really the case, then please fix the code that's shown. Oct 24, 2014 at 15:56

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .