Hello, friends. Well, a picture is worth a thousand words. I would like the behavior on the left rather than on the right, the latters are CircuitTikZ defaults. A helpful guy helped me to do it with independent voltage sources,unfortunately I forgot about asking him for these ones. Does anyone have the same concern out there?
Thanks in advance.
\documentclass{article}
\usepackage{circuitikz}
\makeatletter
\pgfcircdeclarebipole{}{\ctikzvalof{bipoles/vsourceam/height}}{vsourceAM}{\ctikzvalof{bipoles/vsourceam/height}}{\ctikzvalof{bipoles/vsourceam/width}}{ \pgfsetlinewidth{\pgfkeysvalueof{/tikz/circuitikz/bipoles/thickness}\pgfstartlinewidth}
\pgfpathellipse{\pgfpointorigin}{\pgfpoint{0}{\pgf@circ@res@up}}{\pgfpoint{\pgf@circ@res@left}{0}}
\pgfusepath{draw}
\pgfscope \pgftransformxshift{\ctikzvalof{bipoles/vsourceam/margin}\pgf@circ@res@left}
\pgftext[rotate=-\pgf@circ@direction]{$-$}
\pgfusepath{draw}
\endpgfscope
\pgfscope \pgftransformxshift{\ctikzvalof{bipoles/vsourceam/margin}\pgf@circ@res@right}
\pgftext[rotate=-\pgf@circ@direction]{$+$}
\pgfusepath{draw}
\endpgfscope
}
\makeatother
\begin{document}
\begin{circuitikz}[american voltages]
\ctikzset{bipoles/vsourceam/margin=.5}% default too big
\draw (0,0) to[V={v1}] (3,0) to[V={v2}] (3,3) to[V={v3}] (0,3) to[V={v4}] (0,0);
\draw (4,0) to[V={v5}] (6,2);
\end{circuitikz}
\end{document}
As specific code.
\documentclass
and the appropriate packages that sets up the problem. While solving problems can be fun, setting them up is not. Then, those trying to help can simply cut and paste your MWE and get started on solving the problem.