0
\[
 \left| \dfrac{(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)]
 \alpha_k\beta_k z^k}{B(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)] 
 \alpha_k \beta_k z^k -[(A-B)(1-\alpha)][z+\sum_{k=2}^{\infty}[1+\gamma(k-1)]
 \alpha_k \beta_k z^k]}\right|<1
\]
7
  • \[\scriptscriptstyle\left|\frac{...\right|<1\]
    – LaRiFaRi
    Dec 1, 2014 at 6:00
  • @Werner, LaRiFaRi -- This new query by Mittal is not a duplicate of his earlier query. The earlier query was about a multiline equation; this new one is about a single equation that has a very long expression in the denominator. The solution techniques for the earlier query do not apply here.
    – Mico
    Dec 1, 2014 at 6:31
  • 1
    @Mico: True, it may very well not be a duplicate. I just didn't find the question all that useful, nor did it show any research effort at all. In my opinion, a poorly stated question, period.
    – Werner
    Dec 1, 2014 at 6:34
  • @Werner - In that case, the question should be closed because it's not clear what is being asked or because it's low quality, right?
    – Mico
    Dec 1, 2014 at 6:37
  • @Mico Right. But it seems like the OP is having the very same issue as in her/his other post. Over there are 6 nice answers on splitting over-long equations and none has been accepted. DINESH, as shrinking the font size is not really an option (I just posted that comment, as you asked for it later), this "question" is clearly a duplicate on your other post.
    – LaRiFaRi
    Dec 1, 2014 at 6:47

2 Answers 2

5

I suggest you break this equation into two separate expressions: The first to define the numerator term (which also reoccurs in the first part of the denominator) as "C", and the second to express the full result in terms of "C".

Alternatively, you could use the \splitfrac macro of the mathtools package to break the long denominator across two lines. If you choose this method, you'll probably need to place delimiters, e.g., curly braces, around the denominator.

I would not recommend scaling the full expression down to make it fit within the textblock: The font will become so tiny as to be virtually illegible.

enter image description here

\documentclass{article}
\usepackage{mathtools}  % for \splitfrac macro
\usepackage{graphicx}   % for \resizebox macro
\begin{document}

\hrule %% just to illustrate the width of the text block
\bigskip

Put
\[ \textstyle C = (1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)]
 \alpha_k\beta_k z^k\,.
\]
Then
\[
 \left\lvert \dfrac{C}{BC -\bigl[(A-B)(1-\alpha)\bigr]\bigl[z+\sum_{k=2}^{\infty}[1+\gamma(k-1)]
 \alpha_k \beta_k z^k\bigr]}\right\rvert<1\,.
\]


\bigskip
\hrule
\bigskip

\[
\left\lvert \dfrac{(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)]
 \alpha_k\beta_k z^k}{
 \splitfrac{\Bigl\{B(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)] 
 \alpha_k \beta_k z^k }{-\bigl[(A-B)(1-\alpha)\bigr]\bigl[z+\sum_{k=2}^{\infty}[1+\gamma(k-1)]
 \alpha_k \beta_k z^k\bigr]\Bigr\}}}
\right\vert<1\,.
\]

\bigskip
\hrule
\bigskip

Using \verb+\resizebox+ (not recommended!):

\medskip\noindent
\resizebox{\textwidth}{!}{%
$
 \left| \dfrac{(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)]
 \alpha_k\beta_k z^k}{B(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)] 
 \alpha_k \beta_k z^k -[(A-B)(1-\alpha)][z+\sum_{k=2}^{\infty}[1+\gamma(k-1)]
 \alpha_k \beta_k z^k]}\right|<1
$
}

\bigskip
\hrule
\end{document}
2
  • can i small the text size of this equation only Dec 1, 2014 at 5:51
  • @DINESHMITTAL - I've added a solution method that uses the \splitfrac macro of the mathtools package.
    – Mico
    Dec 1, 2014 at 7:03
1

Not if you use landscape layout.

\documentclass{amsart}
\usepackage[landscape]{geometry}
\usepackage{lipsum}
\begin{document}
\lipsum[1]
\[
 \left| \dfrac{(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)]
 \alpha_k\beta_k z^k}{B(1-\beta e^{i\theta}) \sum_{k=2}^{\infty}(k-1)[1+\gamma(k-1)] 
 \alpha_k \beta_k z^k -[(A-B)(1-\alpha)][z+\sum_{k=2}^{\infty}[1+\gamma(k-1)]
 \alpha_k \beta_k z^k]}\right|<1
\]
\end{document}

enter image description here

2
  • but i cannot use one equation as landscape. Dec 1, 2014 at 5:40
  • 3
    What you posted gave almost zero information about your problem, and was not even a question. How is anyone to know you can't use landscape mode, or what kind of document you're working on? Please help us to help you and add a minimal working example (MWE) that illustrates your problem. It will be much easier for us to reproduce your situation and find out what the issue is when we see compilable code, starting with \documentclass{...} and ending with \end{document}.
    – erik
    Dec 1, 2014 at 5:43

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