When then opening and closing of a bracket are not on the same line, LaTeX demands 'invisible' brackets or it will get confused and not compile. Example:

    A = 5 & \left(  a + b + c + ...  \right. \\  % The '\right.' is invisible but needed to close the 'left)
          & \left. d + e + f \right)         

I noticed that this behaviour doesn't work when instead of using \left( you use \Big (or any similar bracket size expression). The following doesn't compile:

    A = 5 & \Big(  a + b + c + ...  \right. 
          & \left. d + e + f \Big)       

It gives the following error:

 ? Missing } inserted.
<inserted text> 
l.20    A = 5 & \Big( a + b + c + ...  \right
                                            . \\

What does this mean and how can I solve it?

  • 7
    with \Big( (or better \Bigl( you do not need to close it: it is a self standing bracket – David Carlisle Dec 7 '14 at 20:34
  • Ah thanks, that actually makes sense of course, as it's more a character of fixed size, rather than an intelligent variable object like \left(. – Jelle Dec 7 '14 at 20:44
  • @DavidCarlisle An answer? – egreg Mar 7 '15 at 21:04

With \Big( (or better \Bigl( you do not need to close it: it is a self standing bracket.

\left \right are different in that they need to see the intervening expression as a single math list in order to determine the size to stretch, which is why they can not span different cells in an align.

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.