An alternative: use of orthogonal coordinate
(p -| q)
refers to the point horizontally aligned with p
and vertically aligned with q
. The -|
was chosen in such a way that it's easy to remember which is which; the -
side is horizontal, and the |
side is vertical. The CircuiTikz manual has further information.
Complete Examples:

Code:
\documentclass[border=10pt,varwidth]{standalone}
\usepackage{tikz}
\usepackage[american,siunitx]{circuitikz}
\usetikzlibrary{calc,positioning}
\begin{document}
An alternative solution
\begin{circuitikz}
\draw
(0,0) node[op amp](opamp){}
(opamp.out) to[short,*-o] (2,0)node[]{} node[right]{$v_{out}$};
\draw (opamp.-) -- ++(-0.2,0) to[R,l_=$R_1$] ++ (-2,0)node[ground,rotate=-90]{};
\draw (opamp.+) to[short,-o] ++ (-0.5,0)node[left]{$V_{in}$};
\draw (opamp.-) to [short,*-] ++(0,1) node{} to [R,l=$R_2$] ([yshift=1cm]opamp.- -|opamp.out);
\end{circuitikz}
\medskip
@Astrinus' solution
\begin{circuitikz}
\draw
(0,0) node[op amp](opamp){}
(opamp.out) to[short,*-o] (2,0)node[]{} node[right]{$v_{out}$};
\draw (opamp.-) -- ++(-0.2,0) to[R,l_=$R_1$] ++ (-2,0)node[ground,rotate=-90]{};
\draw (opamp.+) to[short,-o] ++ (-0.5,0)node[left]{$V_{in}$};
\draw let \p1=(opamp.out),\p2=(opamp.-) in (opamp.-) to [short,*-] ++(0,1)
node{} to [R,l=$R_2$] ++($(\x1,0)-(\x2,0)$);
\end{circuitikz}
\end{document}
\draw let \p1=(opamp.out),\p2=(opamp.-) in (opamp.-) to [short,*-] ++(0,1) node{} to [R,l=$R_2$] ++($(\x1,0)-(\x2,0)$);
Note that you have to\usetikzlibrary{calc}