I'm drawing a molecule and its radicals with chemfig. For the molecule, the bond departs from the C of CH_3, but in the radicals, the departing bond is centered. I tried splitting the \lewis structure and specifying the departure atom with [6,,1], but it didn't help. How can I align the departing bond to the C atom, like is done for the base molecule?

\chemfig{CH_3-[6]*6(------)} \quad \chemfig{\lewis{0.,CH_2}-[6]*6(------)} \quad \chemfig{C\lewis{0.,H_2}-[6,,1]*6(------)}

enter image description here

1 Answer 1


Look at the page 23 of the manual. You have to split CH_2 as follows:

  • Well, I'm glad it was that easy. Thank you!
    – darthbith
    Feb 9, 2015 at 18:07

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.