# Creating a smooth gradient between two colors on an edge in TikZ

I'd like to have a two-colored edge between two nodes of different colors. I'm hoping to make the edge fade from one color into the other in an even way. The solution I've found so far is a bit clumsy, which involves drawing two lines between the same nodes, having each of them fade out in opposite directions with different colors. However, with this solution, the order in which I place the lines matters. Notice the following:

\documentclass{article}
\usepackage{tikz}

\begin{document}

\begin{tikzpicture}
\node[fill=red, circle](0) at (0,0){};
\node[fill=blue, circle](1) at (0,4){};

\end{tikzpicture}$\quad$
\begin{tikzpicture}
\node[fill=red, circle](0) at (0,0){};
\node[fill=blue, circle](1) at (0,4){};

\end{tikzpicture}
\end{document}


So if I draw the blue line second, it will dominate the edge. If I draw the red line second, it will overpower the blue. How can I do this without having to draw two edges on top of each other, and ideally so that the gradient from red to blue is more even?

Edit: I would like to keep the format of defining the paths as connecting between two labeled nodes (i.e. (0) -- (1)) because then I don't have to worry about the direction of the edge. The pictures I'm generating will have a lot of nodes in various places, so the solution I'm looking for should be easily adaptable to this situation. Thanks!

Here is an idea. You can "connect" two nodes using another node, with option sloped, and minimum width equal to the distance between the nodes to connect. The shape of the "connecting" node is by default a rectangle which you can fill with a gradient. But you can even try more exotic node shapes for the "connection".

The following code implements a macro which simplifies the syntax:

% Requires \usetikzlibrary{calc}
\def\connect#1#2#3{%
% #1: starting node
% #2: ending node
% #3: attributes for the shape connecting nodes
\path let
\p1 = ($(#2)-(#1)$),
\n1 = {veclen(\p1)},
\n2 = {atan2(\x1,\y1)} % <- Update
in
(#1) -- (#2) node[#3, midway, sloped, shading angle=\n2+90, minimum width=\n1, inner sep=0pt, #3] {};
}


You can use this macro as in: \connect{A}{B}{options}, being A and B the coordinates to connect and options the ones to be used for the node which fakes the connection. Here you can specify the gradient, as for example:

\begin{tikzpicture}
\foreach \A/\B in {{0,0}/{2,1}, {3,0}/{1,1}} {
\fill [red]  (\A) circle(2pt);
\fill [blue] (\B) circle(2pt);
\connect{\A}{\B}{bottom color=blue, top color=red, minimum height=1pt}
}
\end{tikzpicture}


Which produces:

Note that minimum height specifies in this case the "connection" width.

As said, you can use more exotic shapes as connectors, as for example ellipses:

 % ...
\connect{\A}{\B}{bottom color=blue, top color=red, minimum height=1pt, ellipse}


• This seems pretty great. Let me try to implement it and I'll get back to you. Feb 26 '15 at 17:24

Adding onto JLDiaz's answer--and sorry to wake up such an old post!

I had some trouble with the other solution, I think due to the atan2 typo. According to the Tikz/PGF manual, the argument is in y, x order--I assume to mimic the mathematical atan(y/x). This is why in the given example the +90 is needed to fix the angle in the original code. I have also flipped the top / bottom color order. I will leave my answer below.

I have added labeled nodes and used arrows instead of the default edge shape, but otherwise it is the same as JLDiaz.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calc, shapes.arrows}

\def\connect#1#2#3{%
% #1: starting node
% #2: ending node
% #3: attributes for the shape connecting nodes
\path let
\p1 = ($(#2)-(#1)$),
\n1 = {veclen(\p1)-0.6cm},
\n2 = {atan2(\y1,\x1)} % <- Update
in
(#1) -- (#2) node[#3, midway, rotate = \n2, shading angle = \n2+90, minimum        height=\n1, minimum    width=1pt, inner sep=1pt] {};
}

\begin{document}
\vspace{1cm}

\begin{tikzpicture}
\foreach \A/\B in {{0,0}/{4,2}, {6,0}/{2,2}, {8,0}/{8,2}, {10,2}/{10,0}} {
\connect{\A}{\B}{single arrow, top color=orange, bottom color=blue};
\fill [gray!50] (\A) circle (0.3cm);
\draw           (\A) circle (0.3cm) node {$A$};
\fill [gray!50] (\B) circle (0.3cm);
\draw           (\B) circle (0.3cm) node {$B$};
}
\end{tikzpicture}
\end{document}


And this produces the following image:

• In your code you still have shading angle = \n2+90 but you wrote that the +90 correction isn't needed anymore?
– user30471
May 16 '19 at 21:35