# How to hide the other items completely when I use "pause" operation in beamer?

When I compiling the following codes：

\begin{frame}
\begin{itemize}
\item a
\pause
\item b
\pause
\item c
\end{itemize}
\end{frame}


It's effect is the following:

As we can see that when "a" appears we can also see "b" and "c". I want to know how to hide "b" and "c" completely?

• Please add a minimal working example that takes the form \documentclass{...}\usepackage{....}\begin{document}...\end{document}. If possible, it should compile and have the minimum amount of code needed to illustrate your problem. This makes it much easier for people to help you - and much more likely that they will!
– user30471
May 3 '15 at 13:07
• @Andrew I used an author kit and I was not sure how the effect is controlled. From the answer, I've known it is controlled by \setbeamercovered. Thank you! May 3 '15 at 13:23

This should have been comment but there this can't be put.

This hides them

\documentclass{beamer}
%\setbeamercovered{transparent}
\begin{document}
\begin{frame}
\begin{itemize}
\item a
\pause
\item b
\pause
\item c
\end{itemize}
\end{frame}


It won't if you uncomment the line

%\setbeamercovered{transparent}

• Superb. For so long I was searching for this. It works for me . Jul 10 '16 at 12:08