5

I would like to have a macro which produces N white spaces if called like this

\mulspc{3} % Produces exactly 3 spaces

\newcommand{\mulspc}[1]{
    \newcounter{ctra}
    \setcounter{ctra}{0}
    \whiledo {\value{ctra} < #1}%
    {
      \hspace*{2mm}
      \stepcounter{ctra}
    }
}

But I have problems that this macro does not produce 0mm spacing in a table cell (just at the beginning of the cell!) if I call zero times \multspc{0}. There is always some indent, but where does this come from?

I need this macro to indent some algorithm in the table cell, its nasty but manualy formating gives me the best result in a longtable, because its multiple pages long...

Thanks for your help!

3 Answers 3

13

No need for using a loop:

\newlength\Unit
\setlength\Unit{2mm}
\newcommand\mulspc[1]{\hspace*{#1\Unit}}
        
        
        


foo\mulspc{4}bar
1
  • ...now that's clean! Nice!
    – Werner
    Aug 10, 2011 at 19:26
4

The problem with the current macro is that it unwanted whitespace is added from due to indentation. Add some % add the line ends to get rid of these. However, the current definition also produces a warning after you use \mulspc more than once. That is because the counter definition \newcounter{ctra} is contained within the \newcommand{\mulspc}. Rather define the counter outside the macro definition. Another drawback is that the space offered by \mulspc{0} should be non-existent, which it is not, even if you add % to remove the unwanted spaces. For example, the code:

\documentclass{article}
\usepackage{xifthen}
\newcounter{ctra}%
\newcommand{\mulspc}[1]{
    \setcounter{ctra}{0}%
    \whiledo {\value{ctra} < #1}%
    {\hspace*{2mm}\stepcounter{ctra}}%
}
\begin{document}

\fbox{\mulspc{0}}% Zero spaces

\fbox{}% Empty \fbox

\fbox{\mulspc{1}} % One space

\fbox{\mulspc{3}} % Produces exactly 3 spaces

\end{document}

produces:

Unwanted spacing in \mulspc

To get rid of this spacing, you could use a condition on the parameter passed to \mulspc:

\newcommand{\mulspc}[1]{
  \ifthenelse{#1>0}{%
    \setcounter{ctra}{0}%
    \whiledo {\value{ctra} < #1}%
    {\hspace*{2mm}\stepcounter{ctra}}%
  }{\unskip}%
}

providing \unskip if there is a parameter passed with value less than 1. This produces:

Unwanted spaces gone from \mulspc


Another alternative would be to use the easy interface of the multido package, and define (say)

\usepackage{multido}% A loop facility for Generic TeX
...
\newcommand{\Mulspc}[1]{%
  \multido{\iA=0+1}{#1}{\hspace*{2mm}}%
}

that you can use in a similar way, and is a little cleaner code-wise.

1
  • 1
    That is not because of indentation. Even if you start every line from the first column, a space is still added because of the newline. Aug 10, 2011 at 20:43
1

eTeX is always available nowadays, thus you can simply use

\newcommand\mulspc[1]{\hspace*{#1\dimexpr2mm}}

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