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Here is the code which has an equation in the form of \[... \]:

\documentclass[12pt]{report}
\usepackage{braket}
\usepackage{amssymb}
\usepackage{amsmath}
\begin{document}
\textbf{Proof-} Every element of $\Delta(G)\Delta(G,N)\subset N'$ can be written as \((x-1)y(n-1)\) where \(x,y\in G\) and \(n\in N\). Now, because we can write \((x-1)y=xy-y=(xy-1)-(y-1)\) we also can write every $(g-1)$ in the form : \[g-1=\sum_{i,j}a_{ij}(x_i-1)(n_j-1), \hspace{2pt}\ a_{ij}\in \mathbb{Z}, x_i\in G, n_j\in N \]
\end{document}

My question is how to label the last formula as (*)? All the answers I can find has aligned equations, but in this case I only have one \[...\] equation which I want to label. One way is to use \hspace and then put label, but is there any other way?

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1 Answer 1

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Use the \tag{<your label>} command to insert a custom label as you wish like this \tag{*}:

\documentclass[12pt]{report}
\usepackage{braket}
\usepackage{amssymb}
\usepackage{amsmath}
\begin{document}
\textbf{Proof-} Every element of $\Delta(G)\Delta(G,N)\subset N'$ can be written as \((x-1)y(n-1)\) where \(x,y\in G\) and \(n\in N\). Now, because we can write \((x-1)y=xy-y=(xy-1)-(y-1)\) we also can write every $(g-1)$ in the form : \[g-1=\sum_{i,j}a_{ij}(x_i-1)(n_j-1), \hspace{2pt}\ a_{ij}\in \mathbb{Z}, x_i\in G, n_j\in N \tag{*}\]
\end{document}

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