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This question already has an answer here:

Here is the code which has an equation in the form of \[... \]:

\documentclass[12pt]{report}
\usepackage{braket}
\usepackage{amssymb}
\usepackage{amsmath}
\begin{document}
\textbf{Proof-} Every element of $\Delta(G)\Delta(G,N)\subset N'$ can be written as \((x-1)y(n-1)\) where \(x,y\in G\) and \(n\in N\). Now, because we can write \((x-1)y=xy-y=(xy-1)-(y-1)\) we also can write every $(g-1)$ in the form : \[g-1=\sum_{i,j}a_{ij}(x_i-1)(n_j-1), \hspace{2pt}\ a_{ij}\in \mathbb{Z}, x_i\in G, n_j\in N \]
\end{document}

My question is how to label the last formula as (*)? All the answers I can find has aligned equations, but in this case I only have one \[...\] equation which I want to label. One way is to use \hspace and then put label, but is there any other way?

marked as duplicate by Werner, cfr, Sean Allred, Jesse, Paul Gessler Jul 23 '15 at 3:53

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

5

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Use the \tag{<your label>} command to insert a custom label as you wish like this \tag{*}:

\documentclass[12pt]{report}
\usepackage{braket}
\usepackage{amssymb}
\usepackage{amsmath}
\begin{document}
\textbf{Proof-} Every element of $\Delta(G)\Delta(G,N)\subset N'$ can be written as \((x-1)y(n-1)\) where \(x,y\in G\) and \(n\in N\). Now, because we can write \((x-1)y=xy-y=(xy-1)-(y-1)\) we also can write every $(g-1)$ in the form : \[g-1=\sum_{i,j}a_{ij}(x_i-1)(n_j-1), \hspace{2pt}\ a_{ij}\in \mathbb{Z}, x_i\in G, n_j\in N \tag{*}\]
\end{document}

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