# Molecule positioning in chemfig reaction schemes

I need to write this reaction scheme:

But I can't figure out how to place the NADH molecule like it is in the figure. Help me please, thanks!

Thanks to Clemens' comment, I've worked out this MWE:

\documentclass{article}
\usepackage{chemfig}
\begin{document}
\schemestart
\chemfig{A}
\arrow(aa--){0}[-70,.5]
\chemfig{B}
\arrow(@aa.mid east--.mid west)
\chemfig{C}
\schemestop
\end{document}


• An example with molecule "A" and "B" would be sufficient! Just to understand the positioning. Sep 30, 2015 at 10:15
• this site already has quite a few examples of using chemfig's schemes. Have you already checked those? Sep 30, 2015 at 10:20
• @clemens Googling this thing mostly returned issues about the anchoring points of schemes, I couldn't find one example of free positioning of a molecule. Sep 30, 2015 at 10:27
• There is no free positioning. Either anchors or invisible arrows. I'm sure the site search for chemfig schemes will return some examples Sep 30, 2015 at 10:35
• My comment only was a comment, really. If there was a specific question and its answers that helped you, I'd rather we close this question as duplicate Sep 30, 2015 at 19:36

There is no free positioning. But with the help of invisible arrows it is not too hard:

\documentclass{article}
\usepackage{chemfig}
\setatomsep{1.8em}
\begin{document}

\schemestart
\chemfig{EtO-[:-30](=[6]O)-[:30]-[:-30](=[6]O)-[:30]}
\arrow{0}[-60,.4]
\chemname
{\chemfig{*6(-N(-R)-=(-(=[2]O)-[::-60]NH_2)-(<:[:70]H)(<[:120]H)-=)}}
{NAD$^+$}