I tried this code below but it does not execute and I couldn't find out what is wrong in the equation. What did I do wrong?

$MDAC(t_{i,j}) = max_{ti}\epsilon pred(t_{j})(C_{i,j)$
  • 7
    I think we're all dying to know what MDAC is? :P
    – Au101
    Commented Dec 2, 2015 at 20:41

2 Answers 2


Your primary problem is with (C_{i,j), which should be (C_{i,j}), in other words, you have not paired all your delimeters, you need a closing brace. You should have received the error:

! Missing } inserted.

More generally I would recommend:

$MDAC(t_{j}) = \max_{t_{i} \in pred(t_{j})}(C_{i,j})$

Or perhaps you want?


$MDAC(t_{j}) = \max_{t_{i} \in \pred(t_{j})}(C_{i,j})$

enter image description here

According to others, MDAC is a single unit. It is probably better, therefore, to treat it as an operator and set it upright, but suppose you want it set in italics, you can have:

$\mathit{MDAC}(t_{j}) = \max_{t_{i} \in \pred(t_{j})}(C_{i,j})$

Which will improve the spacing between the letters, treating MDAC as one unit, rather than the product of four separate variables M, D, A and C. For upright typesetting follow Bernard's advice or what I have done with \pred:


$\MDAC(t_{j}) = \max_{t_{i} \in \pred(t_{j})}(C_{i,j})$

enter image description here

  • 2
    "MDAC" should be entered either as \mathrm{MDAC} or as \mathit{MDAC}. Entering it as MDAC induces TeX to typeset it as if were a collection of four separate variables named M, D, A, and C.
    – Mico
    Commented Dec 2, 2015 at 20:34
  • @Mico thanks, fair enough, I'm genuinely unfamiliar with MDAC so I left it alone, for all I knew, it is the product of the three variables M, D and A with C(t_{j}). But I'll edit, although it makes my answer functionally indistinguishable from Bernard's ...
    – Au101
    Commented Dec 2, 2015 at 20:35
  • Well, you can choose the \mathit method to make your solution look different from Bernard's. :-)
    – Mico
    Commented Dec 2, 2015 at 20:37

I don't think MDAC and prec should be typed in italics. I suggest considering them as maths operators, like log, sin, &c., to ensure a correct spacing w. r. t. possible exponents, indices or delimiters.



 $ \MDAC(t_{i,j}) = \max_{t_i\in \pred(t_j)}(C_{i,j}) $ %


enter image description here

  • 1
    Is "MDAC" an operator or the name of a variable? If it's the latter, it's probably better to define \newcommand\MDAC{\mathrm{MDAC}}.
    – Mico
    Commented Dec 2, 2015 at 20:35
  • 3
    @Mico: I wondered. I opted for an operator because it was followed by a pair of parentheses. Maybe the O.P. will tell us.
    – Bernard
    Commented Dec 2, 2015 at 20:38

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