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How can I write (Jx)x∈A in LaTeX? (the second subscript is for parentheses.)

I am trying to write like this, but it's not working: (J}_x)_{x_\in_\textit{A}

Thank you!

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    Hm, difficult to see, what you like to obtain. Maybe $J(x)_{x\in A}$ (this very unusual notation)? I only guessing ... And of course: Welcome to SE!.
    – Zarko
    Jan 4, 2016 at 20:09
  • Well @Zarko, I've already seen that notation for mathematical sequences but with u,n and N not J,x and A so yes that's quite strange in fact!
    – PMC1234
    Jan 4, 2016 at 20:22
  • @PMC1234, to me is more logical $J(x\in A)$ or $J_{x}\big|_{x\in A}$, however, different topics areas, different habits ...
    – Zarko
    Jan 4, 2016 at 20:25
  • Yeah! I got a look on Wikipedia and it differs from countries ! In France we use this notation (u_n)_n\inN, and in anglophone countries they use yours !
    – PMC1234
    Jan 4, 2016 at 20:28
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    I very rarely read french literature (only with lot of pictures, they doesn't require language knowledge :-) ), so in OP question is actually wrong the first} after letter J. She only need to remove it.
    – Zarko
    Jan 4, 2016 at 20:31

2 Answers 2

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Try out ${(J_x)}_{x\in A}$. It works with me.

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  • You are completely right! But when it tends to be separated expressions, they are mandatory so, let's use them every time :-)
    – PMC1234
    Jan 4, 2016 at 20:19
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Well, I will obey Barbara Beeton suggestion:

  • in your code are misplaced curly braces and use of _: instead of (J}_x)_{x_\in_\textit{A} it should be `$(J_x)_{x\in\textit{A}}$ or simpler $(J_x)_{x\in A}$
  • your notation is very unusual, to me is more logical $J(x\in A)$ or $J_{x}\big|_{x\in A}$ or even $J_{x\in A}$.

See examples below:

\documentclass{article}

    \usepackage[active,tightpage]{preview}
\setlength\PreviewBorder{1em}

    \begin{document}
%---------------------------------------------------------------%
    \begin{preview}
    \begin{tabular}{rl}
\verb+$(J_x)_{x\in A }$+: &    $(J_x)_{x\in A}$\\
\verb+$J(x\in A)$+:              &  $J(x\in A)$\\
\verb+$J_{x}\big|_{x\in A}$+:    &  $J_{x}\big|_{x\in A}$\\
\verb+$J_{x\in A}$+:             &  $J_{x\in A}$
    \end{tabular}
    \end{preview}
%---------------------------------------------------------------%
    \end{document}

enter image description here

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