1
\[ \begin{split} 
&( \frac{21! \cdot 2^3}{3! 18! \cdot 4^{18}} + 
\frac{21! \cdot 2^2}{2! 2! 17! \cdot 5^2 \cdot 4^{17}} \\ 
& + \frac{21! \cdot 2}{4! 16! \cdot 5^4 \cdot 4^{16}} + 
frac{21!}{6! 15! \cdot 5^6 \cdot 4^{15}} ) x^{36} \\
&= ( \frac{38138681}{67108864000000} ) x^{36}
\end{split} \]

Is there anything wrong with it? The log doesn't tell me anything useful. Here is the full file:

\documentclass[letterpaper, 12pt, titlepage]{article}
\pagestyle{myheadings} \markright{Fakaff \hfill MATH2P81 \hfill}
\usepackage{amsmath}

\begin{document}

\title{MATH 2P81 \\ Assignment \#1}
\date{\today}
\author{Fakaff \\ \texttt{4847653}}
\maketitle

\begin{enumerate}

\item All terms of the expansion will be of the form $ \binom{21}{a, b, c} 2^a x^b (x^2)^c  $. To 
find the coefficient of $ x^{36} $, we must first find all sets $ \{a, b, c\} $ such that 
$ a + b + c = 21 $ and $ a + b + 2c = 36 $:

$\{3, 0, 18\} $

$ \{2, 2, 17\} $

$ \{1, 4, 16 \} $

$ \{0, 6, 15 \} $

Plugging these numbers into our formula, we get:

\[ \begin{split} 
&( \frac{21! \cdot 2^3}{3! 18! \cdot 4^{18}} + \frac{21! \cdot 2^2}{2! 2! 17! \cdot 5^2 \cdot 4^{17}} \\ 
& + \frac{21! \cdot 2}{4! 16! \cdot 5^4 \cdot 4^{16}} + frac{21!}{6! 15! \cdot 5^6 \cdot 4^{15}} ) x^{36} \\
&= ( \frac{38138681}{67108864000000} ) x^{36}
\end{split} \]

Checking in maple by using the \texttt{expand( (2 - (x/5) + (x^2/4 )^21 )} command confirms this result. 


\end{enumerate}
\end{document}

2 Answers 2

3

You are missing the $s in:

Checking in maple by using the \texttt{expand$(2 - (x/5) + (x^2/4 )^21)$} command confirms this result. 

and you are also missing a \ in a \frac. The full corrected version is below (I have also added a \left(, \right) parenthesis as those will resize based on the vertical height of enclosing text. The left. and \right. are needed as we need to have a matching \left with a `left` on the same line.

\documentclass[letterpaper, 12pt, titlepage]{article}
\pagestyle{myheadings} \markright{Fakaff \hfill MATH2P81 \hfill}
\usepackage{amsmath}

\begin{document}

\title{MATH 2P81 \\ Assignment \#1}
\date{\today}
\author{Fakaff \\ \texttt{4847653}}
\maketitle

\begin{enumerate}

\item All terms of the expansion will be of the form $ \binom{21}{a, b, c} 2^a x^b (x^2)^c  $. To 
find the coefficient of $ x^{36} $, we must first find all sets $ \{a, b, c\} $ such that 
$ a + b + c = 21 $ and $ a + b + 2c = 36 $:

$\{3, 0, 18\} $

$ \{2, 2, 17\} $

$ \{1, 4, 16 \} $

$ \{0, 6, 15 \} $

Plugging these numbers into our formula, we get:

\[ \begin{split} 
&\left( \frac{21! \cdot 2^3}{3! 18! \cdot 4^{18}} + \frac{21! \cdot 2^2}{2! 2! 17! \cdot 5^2 \cdot 4^{17}} \right.\\ 
& \left. + \frac{21! \cdot 2}{4! 16! \cdot 5^4 \cdot 4^{16}} + \frac{21!}{6! 15! \cdot 5^6 \cdot 4^{15}} \right) x^{36} \\
&= \left( \frac{38138681}{67108864000000} \right) x^{36}
\end{split} \]

Checking in maple by using the \texttt{expand$(2 - (x/5) + (x^2/4 )^21)$} command confirms this result. 
\end{enumerate}
\end{document}

If you do not want to format the the text within the \expand, and instead wanted the ^ symbol, you could use:

Checking in maple by using the \texttt{expand(2 - (x/5) + (x\textasciicircum 2/4 )\textasciicircum 21)} command confirms this result. 
0
4

The problem is that the text inside \texttt{} contains math notation, hence you need $ characters, as pointed out by @Peter Grill.

Alternatively you may replace the line in question with:

Checking in maple by using the $\mathtt{expand( (2 - (x/5) + (x^2/4 )^21 )}$ command confirms this result.

which results in the whole expression being typeset with 'typewriter' font, as I guess you intended.

1
  • 1
    Thanks. I was under the impression that texttt was for code. But I found out about \verb now so it's all good :) Sep 18, 2011 at 22:57

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