Copy some of the declarations from mathabx
:
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{libertine}
\usepackage[libertine]{newtxmath}
\usepackage{amsmath}
\DeclareFontFamily{U}{mathx}{\hyphenchar\font45}
\DeclareFontShape{U}{mathx}{m}{n}{<->mathx10}{}
\DeclareFontSubstitution{U}{mathx}{m}{n}
\DeclareSymbolFont{mathx}{U}{mathx}{m}{n}
\DeclareMathSymbol{\intop} {\mathop}{mathx}{"B3}
\DeclareMathSymbol{\iintop} {\mathop}{mathx}{"B4}
\DeclareMathSymbol{\iiintop}{\mathop}{mathx}{"B5}
\DeclareMathSymbol{\ointop} {\mathop}{mathx}{"B6}
\DeclareMathSymbol{\oiintop}{\mathop}{mathx}{"B7}
\begin{document}
This is almost trivial to prove:
\begin{equation*}
\int_{-\infty}^{\infty}e^{-x^{2}}\,dx=\sqrt{\pi}
\end{equation*}
And here are the other integral symbols:
\begin{equation*}
\int\quad\iint\quad\iiint\quad\oint\quad\oiint
\end{equation*}
\end{document}
You may also want to try esint
:
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{libertine}
\usepackage[libertine]{newtxmath}
\usepackage{amsmath}
\usepackage{esint}
\begin{document}
This is almost trivial to prove:
\begin{equation*}
\int_{-\infty}^{\infty}e^{-x^{2}}\,dx=\sqrt{\pi}
\end{equation*}
And here are the other integral symbols:
\begin{equation*}
\int\quad\iint\quad\iiint\quad\oint\quad\oiint
\end{equation*}
\end{document}
A third possibility is to use the cmintegrals
option:
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{libertine}
\usepackage[libertine,cmintegrals]{newtxmath}
\usepackage{amsmath}
\begin{document}
This is almost trivial to prove:
\begin{equation*}
\int_{-\infty}^{\infty}e^{-x^{2}}\,dx=\sqrt{\pi}
\end{equation*}
And here are the other integral symbols:
\begin{equation*}
\int\quad\iint\quad\iiint\quad\oint
\end{equation*}
\end{document}