1

My professor had a nice notation that he used for operators on vector spaces that I thought was clear. It wasn't something like $L: \mathcal{V} \to \mathcal{V}$ but rather a hooked arrow that reinforced that concept that $L$ is a map from $\mathcal{V}$ into itself.

Here is an example of exactly what I am looking for:

enter image description here

  • Welcome to TeX.SX! Are you meaning \hookrightarrow? – egreg Jan 29 '16 at 22:02
  • Hi. No I am looking more for something along the lines of what is picture here: emojipedia-us.s3.amazonaws.com/cache/e2/dd/… but with the upper line being equal length to the lower line. – Johnver Jan 29 '16 at 23:11
  • \hookleftarrow? – Sigur Jan 30 '16 at 0:03
1

Load \usepackage{mathabx} and then

$L: \mathcal{V} \righttoleftarrow$

enter image description here

For more symbols, check here.

  • That is very nice. Thank you. Do you know if there is one with less curvature? – Johnver Jan 30 '16 at 0:16
  • @Johnver, I don't think so. Please, check the link I posted above. – Sigur Jan 30 '16 at 0:18
1

Here is a possibility formed by superimposing a \supset symbol with a small arrowhead using \lefteqn. I used \blacktriangleleft scaled by 50% for the arrowhead.

enter image description here

Then I scaled the whole symbol to 85% (you could adjust this) and wrapped it in a \mathbin for spacing. Note also the use of \colon instead of : for proper spacing of functions.

\documentclass{article}

\usepackage{amssymb} % for \blacktriangleleft symbol
\usepackage{graphicx} % for \scalebox command

\newcommand{\toitself}{\mathbin{\scalebox{.85}{%
    \lefteqn{\scalebox{.5}{$\blacktriangleleft$}}\raisebox{.34ex}{$\supset$}}}}

\begin{document}

$L\colon\mathcal{V}\toitself\mathcal{V}$

\end{document}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.