This is perhaps a 2-parter in that 1) I'd like to have certain equations numbered using the theorem counter (and its associated "style") rather than that built into \begin{equation}. Per MWE, equation (1.1) would then be displayed as 1.3 (w/o parenthesis and bold). And 2) is it possible to display the theorem numbering "split" or centered about a series of equations, much like \split does with equation numbering? I've hacked the \newtheoremstyle to provide the appropriate numbering (as displayed as 1.2 in MWE), but this numbering is outside of the aligned equations. I'm not sure what/where I need to make adjustments. Any ideas would be greatly appreciated.
\documentclass[12pt,leqno]{book}
\usepackage{amsmath, mathtools,amssymb,amscd,amsthm,amstext}
\usepackage{indentfirst}
\usepackage{changepage}
% HACKING \adjustwidth so that it has equal vertical whitespace above/below
\usepackage{etoolbox}
\makeatletter
\apptocmd\adjustwidth{\@inlabelfalse\@newlistfalse}
\makeatother
\setlength\parindent{1.2cm}
% Indentation
\def\changemargin#1#2{\list{}{\rightmargin#2\leftmargin#1}\item[]}
\let\endchangemargin=\endlist
% \swapnumbers puts number ahead of heading - as in 3.4 Definition, rather than Definition 3.4
\swapnumbers
% Redefine theorem style
\newtheoremstyle{mytheoremstyle} % name
{\topsep} % Space above
{\topsep} % Space below
{\itshape} % Body font
{5mm} % Indent amount
{\bfseries} % Theorem head font
{.} % Punctuation after theorem head
{0.5em} % Space after theorem head
{} % Theorem head spec (can be left empty, meaning ‘normal’)
\theoremstyle{mytheoremstyle}
\newtheorem{theorem}{Theorem}[chapter]
\newtheorem{corollary}[theorem]{Corollary}
% Creates a theorem-numbered entry
\newtheoremstyle{dotless}
{}
{}
{}
{}
{\bfseries}
{}
{ }
{}
\theoremstyle{dotless}
\newtheorem{line_eq}[theorem]{}
\begin{document}
\chapter{}
The next result is also an almost immediate consequence of the preceding theorem.
% Corollary 2.5
\begin{adjustwidth}{.6cm}{.6cm}
\begin{corollary}
The additive inverse of an element $a$ of a ring $R$, whose existence is
asserted by Property \textup{\textbf{P}}$_4$, in unique.
\end{corollary}
\noindent\textsc{proof}. To prove this statement, suppose that $a+x= 0$ and that
$a+y=0$. Then $a=x=a+y$, and one of the cancellation laws of addition shows
at once that $x=y$.
\end{adjustwidth}
\vspace{5mm}
\noindent Here's some statements:
\begin{line_eq}
\begin{align*}
&(\textup{i}) & -(-a) &= a, \\
&(\textup{ii}) & -(a+b) &= -a-b, \\
&(\textup{iii}) & -(a-b) &= -a+b, \\
&(\textup{iv}) & (a-b)-c &= a-(b+c). \\
\end{align*}
\end{line_eq}
\noindent
Let us prove the second of these ...
\begin{equation}
a = -(-a)
\end{equation}
\end{document}
\newtagform
and\usetagform
commands defined bymathtools
(see § 3.2 of the documentation).\numberwithin{equation}{chapter}
followed by\newtheorem{theorem}[equation]{Theorem}
did the trick. Thanks, @Bernard.