2

Question is the position of node (16, 20) is mixing with line. How to get rid from this? That is i want to plot this node in right side so there is no chance of collision with line.

This is what i have done so far.

\documentclass[12pt, a4paper]{article}
\usepackage[a4paper,top=1 in,bottom=1 in,left=0.7 in,right=0.7 in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\usepackage{tikz}
\usepackage{pst-tree}
\usetikzlibrary{intersections}
\begin{document}    
\begin{center}
    \begin{tikzpicture}
\draw[thick,latex-latex] (-1,0) -- (13,0)node[right]{$x$};
\draw[thick,latex-latex] (0,-1) -- (0,13)node[above]{$y$};
\node at (-0.3,-0.3) {};
\foreach \x/\l in {,1/2,2/4,3/6,4/8,5/10,6/12,7/14,8/16,9/18,10/20,11/22,12/24}{
    \node[fill,circle,inner sep=1.5pt,label=below:$\l$] at (\x,0) {};
    \node[fill,circle,inner sep=1.5pt,label=left:$\l$] at (0,\x) {};
}
\draw[thick,stealth-stealth, shorten >= -4cm, shorten <= -1cm,name path =b ](2,4) -- (6,8);
\draw[thick,stealth-stealth, shorten >= -1cm, shorten <= -1.5cm,name path =b ](10,8) -- (6,12);
\foreach \x/\y/\name/\m/\n in {4/6//8/12}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {2/4//4/8}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {6/8//12/16}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below :\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {10/8//20/16}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below left:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {8/10//16/20}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below left:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {6/12//12/24}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below left:\name($\m, \n$)}] at (\x,\y) {};
}
\draw (9,11) node[anchor=north west,rotate=0] {$x-y=-4$};
\draw (2.1,13) node[anchor=north west,rotate=0] {$2x-y-2=0$};

\end{tikzpicture}
\end{center}  

\end{document}
  • 1
    If you look at your code, how have you currently positioned that specific label? What do you think you need to change to move it to the right? – Torbjørn T. Feb 8 '16 at 7:27
  • (16, 20) just cutting the line that is only the problem. – SDP Feb 8 '16 at 7:44
  • 1
    You can shift it a little bit to the left with xshift: \foreach \x/\y/\name/\m/\n in {8/10//16/20}{ \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt, xshift=-1mm]left:\name($\m, \n$)}] at (\x,\y) {}; – Ignasi Feb 8 '16 at 8:00
3

I've changed below to right and changed inner sep= to 3pt in your code:

\documentclass[12pt, a4paper]{article}
\usepackage[a4paper,top=1 in,bottom=1 in,left=0.7 in,right=0.7 in]{geometry}
\usepackage[utf8]{inputenc}
%\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\usepackage{tikz}
\usepackage{pst-tree}
\usetikzlibrary{intersections}
\begin{document}    
\begin{center}
    \begin{tikzpicture}
\draw[thick,latex-latex] (-1,0) -- (13,0)node[right]{$x$};
\draw[thick,latex-latex] (0,-1) -- (0,13)node[above]{$y$};
\node at (-0.3,-0.3) {};
\foreach \x/\l in {,1/2,2/4,3/6,4/8,5/10,6/12,7/14,8/16,9/18,10/20,11/22,12/24}{
    \node[fill,circle,inner sep=1.5pt,label=below:$\l$] at (\x,0) {};
    \node[fill,circle,inner sep=1.5pt,label=left:$\l$] at (0,\x) {};
}
\draw[thick,stealth-stealth, shorten >= -4cm, shorten <= -1cm,name path =b ](2,4) -- (6,8);
\draw[thick,stealth-stealth, shorten >= -1cm, shorten <= -1.5cm,name path =b ](10,8) -- (6,12);
\foreach \x/\y/\name/\m/\n in {4/6//8/12}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {2/4//4/8}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {6/8//12/16}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {10/8//20/16}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below left:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {8/10//16/20}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=3pt]right:\name($\m, \n$)}] at (\x,\y) {};
}
\foreach \x/\y/\name/\m/\n in {6/12//12/24}{
    \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]below left:\name($\m, \n$)}] at (\x,\y) {};
}

\draw (9,11) node[anchor=north west,rotate=0] {$x-y=-4$};
\draw (2.1,13) node[anchor=north west,rotate=0] {$2x-y-2=0$};

\end{tikzpicture}
\end{center}  

\end{document}

With the following output:

enter image description here

Additional note by Torbjørn T.: I don't really see why you use \foreach for the point labels, in none of the cases do you actually loop over multiple entries in a list. However, by adding one more iteration variable for the position you can add all the labels with one loop:

\documentclass[12pt, a4paper]{article}
\usepackage{tikz}
\usetikzlibrary{intersections}
\begin{document}    
\begin{center}
\begin{tikzpicture}
\draw[thick,latex-latex] (-1,0) -- (13,0)node[right]{$x$};
\draw[thick,latex-latex] (0,-1) -- (0,13)node[above]{$y$};
\node at (-0.3,-0.3) {};
\foreach \x/\l in {,1/2,2/4,3/6,4/8,5/10,6/12,7/14,8/16,9/18,10/20,11/22,12/24}{
    \node[fill,circle,inner sep=1.5pt,label=below:$\l$] at (\x,0) {};
    \node[fill,circle,inner sep=1.5pt,label=left:$\l$] at (0,\x) {};
}
\draw[thick,stealth-stealth, shorten >= -4cm, shorten <= -1cm,name path =b ](2,4) -- (6,8);
\draw[thick,stealth-stealth, shorten >= -1cm, shorten <= -1.5cm,name path =b ](10,8) -- (6,12);
\foreach \x/\y/\name/\m/\n/\pos in
  {4/6//8/12/below right,
   2/4//4/8/below right,
   6/8//12/16/below right,
   10/8/\hspace{3pt}/20/16/below left,
   8/10//16/20/right,
   6/12//12/24/below left}
{
 \node[fill,circle,inner sep=2.5pt,label={[inner sep=0pt]\pos:\name($\m, \n$)}] at (\x,\y) {};
}
\draw (9,11) node[anchor=north west,rotate=0] {$x-y=-4$};
\draw (2.1,13) node[anchor=north west,rotate=0] {$2x-y-2=0$};
\end{tikzpicture}
\end{center}  
\end{document}
| improve this answer | |
  • This is exactly what i want and one more thing thanks to ignasi – SDP Feb 8 '16 at 8:34
  • 1
    I don't think what I added was reason enough to post a new answer, so I took the liberty of adding it to yours. Feel free to roll back my edit if you don't think like it. – Torbjørn T. Feb 8 '16 at 11:59
  • @Torbjørn T., No that's great! I always appreciate a better solution, thanks for editing. – Octopus Feb 8 '16 at 12:36

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