I'm working on this code
\documentclass[a4paper]{standalone}
\usepackage{amssymb,tikz}
\usetikzlibrary{positioning, calc}
\begin{document}
\newcounter{compteur}
\setcounter{compteur}{1}
\newcounter{lettres}
\setcounter{lettres}{1}
\begin{tikzpicture}
\node[matrix, inner sep=0](truc){
\node[anchor=west, inner sep=0](question){Question~\thecompteur};
\addtocounter{compteur}{1}
\node[right=of question](carre\thelettres){$\square$};
\node[above =\baselineskip of carre\thelettres]{\Alph{lettres}};
\stepcounter{lettres}
\foreach\x [evaluate = \x as \y using int(\x+1)] in {1,...,4}{
\node[right=of carre\x](carre\y){$\square$};
\node[above =\baselineskip of carre\thelettres]{\Alph{lettres}};
\stepcounter{lettres}
}
\foreach\a in{2,...,15}{
\node[anchor=east, below=\baselineskip of question, inner sep=0](question){Question~\thecompteur};
\foreach\b in {1,...,5}{
\path let \p1=(question), \p2=(carre\b) in node at (\x2,\y1){$\square$};
}
\addtocounter{compteur}{1}
}
\\
};
\end{tikzpicture}
\end{document}
that compiles into :
My problem is I would like to have several tables of this kind juxtaposed like some elements of another 6 rows/2columns matrix in which the 1st row/2nd column table element would have its first question labelled "Question 16" and so on.
Does a simple code solve this?