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The symbol I'm looking for is similar to the one produced by \mathfrak{X}, but with a Y instead of an X. I've spent hours looking for this, combed through every character list I can find, tried detexify, and I can't find the answer anywhere. If this question has been asked before, I apologize, please direct me to it, I've looked and haven't found it. Thanks!

  • Welcome to TeX.SX! Should the Y be fraktur too? – egreg Jun 13 '16 at 19:50
  • 2
    Have you got any picture of your Y? I hope that it is not the symbol of yen... – Przemysław Scherwentke Jun 13 '16 at 19:52
  • @egreg Yes, it is exactly like the X, just with a Y. And no,@Przemysław Scherwentke, it is not the symbol for yen. Let me figure out how to upload a picture and I will. – A. R. Jun 13 '16 at 19:55
  • @PrzemysławScherwentke I can't upload a picture, so here's a work-around. Go to this link, you can preview the book. The character I'm looking for is at the top of page 231. – A. R. Jun 13 '16 at 20:11
  • Is it an article of Wojbor Wojczyński? I have not previev of this page, but a visible part is from pre-computer era. – Przemysław Scherwentke Jun 13 '16 at 20:22
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Since it is not exactly clear if you want a normal "Y" or a fraktur "Y", I provide both... (note that these are designed to take up the same space as an unadulterated "Y" or \mathfrak{Y})

The stoke elevation can be adjusted with the first argument of \stackengine.

\documentclass{article}
\usepackage{amssymb}
\usepackage{stackengine}
\def\strokeY{\ensurestackMath{\stackengine{0pt}{-\,}{Y}{O}{c}{F}{T}{L}}}
\def\strokefracY{\ensurestackMath{\stackengine{0pt}{\,-}{\mathfrak{Y}}{O}{c}{F}{T}{L}}}
\begin{document}
$\strokeY =  X$

$\strokefracY =  X$
\end{document}

enter image description here

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