# How can I draw edges from node to the same node itself?

I use tikz to draw a three nodes in a triangle, connected by arrows. I want to add a rounded edge from each node to itself, basically adding edges like \path[<->] (left) edge (left) to the example below. However, it seems that it does not seem to work like this. Can anyone give me a hint on how to approach this/where to look?

\begin{tikzpicture}
\draw(0,0)node[left] (left){news media };
\draw(5,0)node[right] (right) {citizens};
\draw(60:5)node[above] (above){political actors};
\path[<->] (left) edge (right);
\path[<->] (left) edge (above);
\path[<->] (above) edge (right);
\end{tikzpicture}

• Welcome to TeX.SX. You mean something like the option loop left, described in section 70.4 in the pgfmanual on page 748? Aug 12, 2016 at 10:31
• Thanks, @Stefan! Exactly that! I just did not know where to look. If your comment were an answer, I'd accept it ;-) Aug 12, 2016 at 10:45

As already stated in the comment below the question this can be achieved using the loop options described in section 70.4 in the pgfmanual (v3.0.1a) on page 748. Applied to your given example it would be something like

\documentclass[border=2mm]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}
\draw(0,0)node[left] (left){news media };
\draw(5,0)node[right] (right) {citizens};
\draw(60:5)node[above] (above){political actors};
\path[<->] (left)
edge (right)
edge [loop left] node {bla} ()
;
\path[<->] (right)
edge (above)
edge [loop right] node {bli} ()
;
\path[<->] (above)
edge (left)
edge [loop above] node {blub} ()
;
\end{tikzpicture}
\end{document}


which gives the following result