3

As a learning exercise I have been trying to replicate the structure of LSD using chemfig. I've taken this figure for reference.

My best effort so far has been this...

\documentclass[border=10pt]{standalone}
\usepackage[version=3]{mhchem} % Package for chemical equation typesetting
\usepackage{chemfig}
\begin{document}
\chemfig{*6(=(*5(-N-=(*6(--([:-30]<H)(*6(-N(-)--([:120]<:H)(-([:30]=O)([::60]-N([:180]-[::45]-)([:60]-[:10]-)))-=-))---))--))-=-=-)}
\end{document}

which produces ...

enter image description here

I have not been able to figure out how to create the proper triple ring nor have I gotten a proper understanding of the bond angles on the two chains off the N.

I would certainly appreciate any and all advice.

2

Here's how I would do it, although I admit I'm not very expert with chemfig.

Output

enter image description here

Code

\documentclass[border=10pt]{standalone}
\usepackage[version=3]{mhchem} % Package for chemical equation typesetting
\usepackage{chemfig}
\begin{document}
\chemfig{*6(=(-[:-70]N-[:0]=[:70])-(*6(---(*6(([:90]<H)-
N(-[:-30]CH_3)--(-[:90](=[:30]O)-[:145]N(-[:210]-[:150])
(--[:150]))([:145]<:H)-=))---))=-=-)} 
\end{document}

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