# Aligning molecule name within a reaction using chemname

I want to align the chemical names of my components without moving the structure. Does someone have an idea how that works?

\schemedebug{true}
\schemestart
\setcrambond{2pt}{}{}
\chemname{\chemfig{H-[2,0.5](-[2,0.5]OH)-[,,,,
line width=2pt](-[6,0.5]OH)(-[2,0.5]H)>[1,0.7](-[6,0.5]OH)(-[2,0.5]H)-[3,0.7]
O-[4]?(-[2,0.3]-[3,0.5]OH)-[5,0.7](-[2,0.5]H)(-[6,0.5,,2]HO)<[7,0.7]}}{D-Glukose}
2 \arrow{0}[,0]\chemname{\setatomsep{1.78500em}\chemfig{-[2](=[:150]O)-[:30](=[2]O)-[:-30]O^{-}}}{Pyruvat}
2 \arrow{0}[,0]\chemname{\setatomsep{1.78500em}\chemfig{-[2](-[:150]OH)-[:30](=[2]O)-[:-30]O^{-}}}{Lactat}
\schemestop
\chemnameinit{}


If you use \arrow(.base east--.base west) you'll see that \chemname does use the correct depth. The secret is choosing a suitable baseline for the molecules (remember that always the first atom inside a chemfig formula determines the baseline of the whole molecule).

\documentclass{article}
\usepackage{chemfig}
% \usepackage{showframe}
\begin{document}

\setatomsep{1.78500em}
\setcrambond{2pt}{}{}
\schemestart
\setatomsep{1.5em}
\chemname{%
\chemfig{
-[1,1.4](-[2]-[3]HO)-[,2]O-[7,1.4]
(-[2]H)(-[6]OH)
<[5,1.4](-[2]H)(-[6]OH)
-[4,2,,,line width=2pt](-[2]H)(-[6]OH)
>[3,1.4](-[6]H)(-[2]OH)
}%
}{D-Glukose}