4

I have

\usepackage{romannum}
\usepackage{amsmath}
\usepackage{mathtools}  

How is it possible to write enter image description here

using

\begin{subequations}
\begin{align}
...
\end{align}
\end{subequations}

The code is shown below:

\documentclass{article}
\usepackage{romannum}
\usepackage[english]{babel}
\usepackage[utf8]{inputenc}
\usepackage{fancyhdr}
\usepackage{geometry}
\geometry{legalpaper, portrait, margin=1.3in}
\usepackage{anyfontsize}
\usepackage{svg}
\usepackage{t1enc}
\pagestyle{fancy}
\fancyhf{}
\usepackage{amsmath}
\lhead{Small time solution from (15a,b)}
\rfoot{Page \thepage}
\usepackage[titletoc,toc]{appendix}
\usepackage{graphicx,amssymb,amstext}
\usepackage{graphicx}
%\usepackage[]{mcode}
\usepackage{xcolor}
\usepackage{titlesec}
\usepackage{hyperref}
\usepackage{xcolor}
\usepackage{cleveref}
\usepackage{nameref}
\usepackage{cite}
\usepackage{enumerate}
\usepackage{amssymb}     
\usepackage{mathtools}               %  new commands %
\newcommand \bprime {\backprime\hspace{-.11em}      }   %  backstroke
\newcommand \xprime {\prime\hspace{-.25em}\backprime}   %  cross
\showoutput
\showboxdepth3

\titleformat{\section}
  {\normalfont\Large\bfseries}   % The style of the section title
  {}                             % a prefix
  {0pt}                          % How much space exists between the prefix and the title
  {Section \thesection:\quad}    % How the section is represented
% Starred variant
\titleformat{name=\section,numberless}
  {\normalfont\Large\bfseries}
  {}
  {0pt}
  {}
\begin{document}
\begin{subequations}
\begin{align}
h^{''}  = \frac{1}{2}  -  \underbrace{\frac{\Big(h(T) + (1-b) \theta (T) \Big)^2}{4 A \sqrt{A \kappa}}}_\text{\Romannum{1}} \Big\{ \underbrace{\frac{(1 - C) \sqrt{\frac{\kappa}{A}}}{(1+(1-C)^2 \frac{\kappa}{A})}}_\text{\Romannum{2}}+ \underbrace{ \frac{C \sqrt{\frac{\kappa}{A}}}{(1+ C^2 \frac{\kappa}{A})}}_\text{\Romannum{3}}  + \underbrace{ \arctan \Big(\frac{\sqrt{\frac{\kappa}{A}}}{1 - C (1-C) \frac{\kappa}{A}}\Big)}_\text{\Romannum{4}} \Big\}  - M \hat g, 
\\
\Gamma \theta^{''} = \frac{1}{2} \bigg( \frac{1}{2} - b   - \underbrace{\Big(h(T) + (1-b) \theta (T) \Big)^2}_\text{\Romannum{5}}  \bigg\{ -\frac{1}{2A \kappa} \bigg( \underbrace{\frac{1}{(1+ (1-C)^2 \frac{\kappa}{A})}}_\text{\Romannum{6}} - \underbrace{\frac{1}{(1+C^2 \frac{\kappa}{A})}}_\text{\Romannum{7}}\bigg) 
\\
+ \underbrace{ \frac{(C-b)}{2 A \sqrt{A\kappa}}}_\text{\Romannum{8}}  \Big\{ \underbrace{ \frac{(1 - C) \sqrt{\frac{\kappa}{A}}}{(1+(1-C)^2 \frac{\kappa}{A})}}_\text{\Romannum{9}} + \underbrace{ \frac{C \sqrt{\frac{\kappa}{A}}}{(1+ C^2 \frac{\kappa}{A})}}_\text{\Romannum{10}}  + \underbrace{ \arctan \Big(\frac{\sqrt{\frac{\kappa}{A}}}{1 - C (1-C) \frac{\kappa}{A}}\Big) }_\text{\Romannum{11}}\Big\} \bigg\} \bigg) .
\end{align}
\end{subequations}
\\
\end{document}
  • Welcome to TeX SX! Could you post a full compilable code that we can play with? Also, should the roman numbering be done by hand or automatically? – Bernard Oct 1 '16 at 23:22
  • Thanks @Bernard. I have just posted full code. Roman numbers should be shown automatically by \usepackage{romannum} package . – Meva Oct 1 '16 at 23:39
  • Will you have to cross-reference these subformulae? And will these numbers have to be reset at each equation? – Bernard Oct 2 '16 at 1:21
  • Yes @Bernard, they have to be used in subequations like above. The reason for that is the equations are so long and I have to get (a), (b) tags for these two equations above. Equation numbering should be done automatically when compiling not manually. – Meva Oct 2 '16 at 1:53
  • I personally would recommend using tikzmark to add the braces. That way you can separate the drawing from the content. Examples include: Underbrace under sqrt content, How avoid that the Underbrace Outside the delimiters $| |$ appear inside the delimiters and Using \underbrace with table columns. – Peter Grill Oct 2 '16 at 2:32
5

Introduced a new command \romanbrace

enter image description here

\documentclass{article}

\usepackage{amsmath}
\newcounter{fudge}
\renewcommand\thefudge{\textnormal{\Roman{fudge}}}
\newcommand{\ouch}{\refstepcounter{fudge}\thefudge}
\newcommand{\romanbrace}[1]{\underbrace{#1}_{\ouch}}
\begin{document}

\begin{subequations}
\begin{align}
 y&= t_hi_s + i_s + \romanbrace{c_r a_z y!} \\
 z&= \romanbrace{s_tu_pi_d}
\end{align}
\end{subequations}
\end{document}
  • 1
    I think you've solved the OP's first issue, viz., how to get the "label" below each underbrace to be incremented automatically and to be displayed in Roman numerals. I think the OP also wants to be able to cross-reference the braced items; can your approach accomplish this? (Incidentally, I've made your code a bit more "LaTeX-y"; feel free to revert.) – Mico Oct 2 '16 at 8:34
  • 2
    \romanbrace -- nice touch! :-) – Mico Oct 2 '16 at 14:51
2

Some suggestions

  • Get rid of as much visual clutter as possible. Omit unneeded parentheses, keep the size of various groups of parentheses consistent, and assure that the underbraces are all at the same depth. (In the code below, look for a couple of \vphantom statements.) Choose line breaks so that none of the equation material protrudes into the margin.

  • Don't load any given package more than once. Also, don't load packages in a redundant way: the amstext package is loaded automatically by the amsmath package which, in turn, is loaded automatically by the mathtools package.

  • Align the = symbols in rows 1 and 3 relative to each other, and indent the material on lines 2 and 4.

  • Use a dedicated counter -- called romcount in the code below -- and set its appearance to be uppercase-Roman. Then, set up a macro (called \romantag in the code below) increments and displays this counter; use this macro in the second argument of the various \underbrace statements.

enter image description here

\documentclass{article}
\usepackage[english]{babel}
\usepackage[utf8]{inputenc}
\usepackage{fancyhdr}
\usepackage{geometry}
\geometry{legalpaper, portrait, margin=1.3in}
\usepackage{svg}
\usepackage{t1enc}
\pagestyle{fancy}
\fancyhf{}
\lhead{Small time solution from (15a,b)}
\rfoot{Page \thepage}

\usepackage[titletoc,toc]{appendix}
\usepackage{graphicx,amssymb}%%%,amstext}
%%%\usepackage{amsmath}
%%%\usepackage{graphicx}
%\usepackage[]{mcode}
\usepackage{xcolor}
\usepackage{titlesec}
%%%\usepackage{xcolor}
\usepackage{cite}
\usepackage{enumerate}
%%%\usepackage{amssymb}     
\usepackage{mathtools}  

\usepackage[colorlinks]{hyperref}
\usepackage[nameinlink,noabbrev]{cleveref}
\usepackage{nameref}

\titleformat{\section}
  {\normalfont\Large\bfseries}   % The style of the section title
  {}                             % a prefix
  {0pt}                          % How much space exists between the prefix and the title
  {Section \thesection:\quad}    % How the section is represented
% Starred variant
\titleformat{name=\section,numberless}
  {\normalfont\Large\bfseries}
  {}
  {0pt}
  {}

\newcounter{romcount}
\renewcommand\theromcount{\Roman{romcount}}
\newcommand\romantag{\stepcounter{romcount}\textnormal{\theromcount}}

\begin{document}
\begin{subequations}
\begin{align}
h''  &= \frac{1}{2}  - M \hat g  \notag\\
&\qquad-
\underbrace{\frac{\bigl(h(T) + (1-b) \theta (T) \bigr)^2}{4 A \sqrt{A \kappa}}}_{\romantag} \biggl\{ 
\underbrace{\frac{(1 - C) \sqrt{\frac{\kappa}{A}}}{1+(1-C)^2 \frac{\kappa}{A}}}_{\romantag}+ 
\underbrace{ \frac{C \sqrt{\frac{\kappa}{A}}}{1+ C^2 \frac{\kappa}{A}}}_{\romantag}  + 
\underbrace{ \arctan \frac{\sqrt{\frac{\kappa}{A}}}{1 - C (1-C) \frac{\kappa}{A}}}_{\romantag} \biggr\} \,, \label{eq:first}\\
\Gamma \theta'' &= 
\frac{1}{2} \bigg[ \frac{1}{2} - b   - 
\underbrace{\bigl(h(T) + (1-b) \theta (T) \vphantom{\frac{1}{\frac{\kappa}{A}}}\bigr)^2}_{\romantag}  
\biggl\{ -\frac{1}{2A \kappa} \bigg( 
\underbrace{\frac{1}{1+ (1-C)^2 \frac{\kappa}{A}}}_{\romantag} - 
\underbrace{\frac{1}{1+C^2 \frac{\kappa}{A}}}_{\romantag}\bigg)  \notag \\
&\qquad+ 
\underbrace{ \frac{C-b}{2 A \sqrt{A\kappa}}\vphantom{\frac{1}{\frac{\kappa}{A}}}}_{\romantag}  \biggl( 
\underbrace{ \frac{(1 - C) \sqrt{\frac{\kappa}{A}}}{1+(1-C)^2 \frac{\kappa}{A}}}_{\romantag} + 
\underbrace{ \frac{C \sqrt{\frac{\kappa}{A}}}{1+ C^2 \frac{\kappa}{A}}}_{\romantag}  + 
\underbrace{ \arctan \frac{\sqrt{\frac{\kappa}{A}}}{1 - C (1-C) \frac{\kappa}{A}} }_{\romantag}
\biggr) \biggr\} \bigg] \,. \label{eq:second}
\end{align}
\end{subequations}

\end{document}
  • All good comments. – JPi Oct 2 '16 at 20:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.