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I am currently drawing the molecular structure of Benzocyclobutene (BCB). I want it to look like this

The BCB structure

My LaTex code looks currently like:

\documentclass{article}
\usepackage{chemfig}
\renewcommand*\printatom[1]{\ensuremath{\mathsf{#1}}}
\begin{document}

%\setcrambond{2pt}{}{}
\chemfig{*4(-(**6(---(-[0,1]=[:-45,1]-[0,1]Si(-[:90,1]CH_3)(-O-Si(-[:90,1]CH_3)(-[:-90,1]CH_3)(-=[:45,1]- **6(---(*4(----)\quad)---)\quad ))(-[:-90,1]CH_3))--))---)\quad}

\end{document}

which gives the following output The result of my code

Any good ideas how to shift the ring inside the aromatic ring? And also right group has to be rotated.

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Like this? [Disclimer: I have no idea what I am doing, just played around with the angles.]

\documentclass{article}
\usepackage{chemfig}
\renewcommand*\printatom[1]{\ensuremath{\mathsf{#1}}}
\begin{document}

\setcrambond{2pt}{}{}
\chemfig{*4(-(**6(---(-[0,1]=[:-45,1]-[0,1]Si(-[:90,1]CH_3)(-[:0,1]O-[:0,1]Si(-[:90,1]CH_3)(-[:-90,1]CH_3)([:0,1]-=[:45,1]-[:0] **6([:-30]---(*4(----)\quad)---)\quad ))(-[:-90,1]CH_3))--))---)\quad}

\end{document}

enter image description here

  • @user3364924 Good to hear that the answer helped you. If you are satisfied with the solution, please consider accepting it (by clicking on the checkmark ✓, see How do you accept an answer?). This shows others that the question is solved and will remove it from the list of unanswered questions. As a bonus, this will not only give a reward to the answer, but you will get 2 reputation points, too. – user36296 Dec 15 '16 at 8:32

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