I need to draw first a rectangle with curvy looking edges. Then I need a rectangle with curvy looking edges and also rounded corners. But the corners need to be inverted (pointing inwards). I have made a handmade drawing for illustration:

enter image description here

  • 1
    You should load your sketch into your question. And also show what you try so far. Your shapes can be drawn with bending lines.
    – Zarko
    Dec 1, 2016 at 21:45
  • 1
    @Zarko I'm not sure new users can do this. They can upload it and post a link, but I don't think they can allow it to be displayed. (But I'm not certain about this.)
    – cfr
    Dec 2, 2016 at 13:41
  • 1
    @cfr, new user can't do this, it had to earned some minimal reputation (15) for this. I'm also not certain about the limit ...
    – Zarko
    Dec 2, 2016 at 13:53
  • 2
    I'm voting to close this question as off-topic because this is a just-do-it-for-me question (-1). Jun 26, 2019 at 12:06

2 Answers 2


Note that I think I ought not answer 'do-it-all-for-me's such as this one. Also, be aware that I am much less likely to be responsive to follow-ups in such cases, unless your follow-up happens to appeal to me. If you want any adjustments, I therefore recommend that you desire the addition of one or more of the following:

  1. one or more cats, sitting or lying;
  2. one or more cauldrons;
  3. one or more trams or single-decker buses.

  \draw (0,0) coordinate (a) [bend right=15] to +(2,0) coordinate (b) [bend right] to +(0,-1) coordinate (c) [bend right] to (a |- c) [bend right=15] to cycle ;
    \clip (3,0) coordinate (A) +(.1,0) coordinate (A1) -- +(1.9,0) coordinate (B1) arc (180:270:.1) coordinate (B2) -- +(0,-.8) coordinate (C1) arc (90:190:.1) coordinate (C2) -- (C2 -| A1) arc (0:90:.1) -- (B2 -| A) arc (270:360:.1) ;
    \draw (A) coordinate (a') [bend right=15] to +(2,0) coordinate (b') [bend right] to +(0,-1) coordinate (c') [bend right] to (a' |- c') [bend right=15] to cycle ;
  \clip (a') [bend right=15] to (b') [bend right] to (c') [bend right] to (a' |- c') [bend right=15] to cycle ;
  \draw   (B1) arc (180:270:.1)  (C1) arc (90:190:.1)  (C2 -| A1) arc (0:90:.1)  (B2 -| A) arc (270:360:.1) ;

bitten bendy box

  • you are good soul and hard worker bee (+1) /literally translated, i don't know the adequate English phrase/
    – Zarko
    Dec 1, 2016 at 23:47
  • @Zarko I was just slightly intrigued, for some reason. No good if you want them to be nodes, of course, but I liked the idea of a bitten-bendy-box.
    – cfr
    Dec 1, 2016 at 23:55
  • @Zarko I don't know if there is an exact English phrase, but I think I get the idea. We shall have to ask Alan Munn.
    – cfr
    Dec 1, 2016 at 23:56
  • Thank you cfr! There is no need for cats or buses. But thanks for the offer. ;-) Dec 2, 2016 at 8:42

This is not a full answer unfortunately, but I needed a very similar shape: a rectangle with inverted corners, but not the convex edges. I made a shape (see here: myshape.tex) for it, in which the corners to invert can be selected: enter image description here

The test script is rather small:

  shape example/.style={
    line width=.5cm,



  \node[rectangle with inverted corners, rectangle with inverted corners radius=20pt,
        rectangle with inverted corners selected={north west, north east},
        shape example, minimum height=6cm, inner ysep=1cm, inner xsep=.75cm] (s)
    {Rectangle with inverted corners\vrule width1pt height2cm};
  \foreach \anchor/\placement in
    {text/below, center/above, 70/above,
     base/below, base east/below, base west/below,
     mid/above, mid east/above, mid west/above,
     north/below, south/above, east/above, west/above,
     before north east/above, north east/below, after north east/above,
     before north west/above, north west/below, after north west/above,
     before south west/above, south west/above, after south west/below,
     before south east/below, south east/above, after south east/above}
  \draw[shift=(s.\anchor)] plot[mark=x] coordinates{(0,0)}
    node[\placement=0mm] {\scriptsize\texttt{(s.\anchor)}};


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