Triangle issue in Latex

Question

Hy can someone please give me a little hand here. I want to make this triangle.

How to find middle point in triangle? However can someone point me, this is what I have so far.

\documentclass[border=5mm,tikz]{standalone}
\usetikzlibrary{angles,arrows.meta}
\begin{document}
\begin{tikzpicture}[scale=2]
  \coordinate (A) at (0,0);
  \coordinate (B) at (0,1);
  \coordinate (C) at (1.7,0);
  \draw (A) -- (B) -- (C) -- (A);

\end{tikzpicture}
\end{document}

I'd really appreciate if some could help me.

Answer 1

TikZ has powerful libraries which you can use. The angles,quotes are helpful for drawing the angles with anotations, and the intersections can be used to find the middle point X in the triangle. Also note how to find the point (a) using the perpendicular coordinates \coordinate (a) at ($(C)!(A)!(B)$);, which means the projection of A onto CB.

\documentclass[border=5mm,tikz]{standalone}
\usetikzlibrary{arrows.meta,calc,angles,quotes,intersections}
\begin{document}
\begin{tikzpicture}[scale=2]
  \coordinate (A) at (0,0);
  \coordinate (B) at (0,1);
  \coordinate (C) at (1.7,0);
  \coordinate (a) at ($(C)!(A)!(B)$);
  \coordinate (w) at ($(A)!0.3!(C)$);
  \draw (A) -- (B) -- (C) -- (A) -- (a);
  \draw[shorten >=-7pt] (B)--(w) node[below right]{w};
  \coordinate (X) at (intersection of A--a and B--w);
  \draw pic["$\cdot$", draw, angle radius=2mm] {angle=B--a--A}
        pic["$\cdot$", draw, angle radius=2mm] {angle=C--A--B}
        pic["$\varepsilon$", draw, angle radius=3mm] {angle=w--X--a};
\end{tikzpicture}
\end{document}