# Triangle issue in Latex

Hy can someone please give me a little hand here. I want to make this triangle. How to find middle point in triangle? However can someone point me, this is what I have so far.

\documentclass[border=5mm,tikz]{standalone}
\usetikzlibrary{angles,arrows.meta}
\begin{document}
\begin{tikzpicture}[scale=2]
\coordinate (A) at (0,0);
\coordinate (B) at (0,1);
\coordinate (C) at (1.7,0);
\draw (A) -- (B) -- (C) -- (A);

\end{tikzpicture}
\end{document}


I'd really appreciate if some could help me.

TikZ has powerful libraries which you can use. The angles,quotes are helpful for drawing the angles with anotations, and the intersections can be used to find the middle point X in the triangle. Also note how to find the point (a) using the perpendicular coordinates \coordinate (a) at ($(C)!(A)!(B)$);, which means the projection of A onto CB.

\documentclass[border=5mm,tikz]{standalone}
\usetikzlibrary{arrows.meta,calc,angles,quotes,intersections}
\begin{document}
\begin{tikzpicture}[scale=2]
\coordinate (A) at (0,0);
\coordinate (B) at (0,1);
\coordinate (C) at (1.7,0);
\coordinate (a) at ($(C)!(A)!(B)$);
\coordinate (w) at ($(A)!0.3!(C)$);
\draw (A) -- (B) -- (C) -- (A) -- (a);
\draw[shorten >=-7pt] (B)--(w) node[below right]{w};
\coordinate (X) at (intersection of A--a and B--w);
\draw pic["$\cdot$", draw, angle radius=2mm] {angle=B--a--A}
pic["$\cdot$", draw, angle radius=2mm] {angle=C--A--B}
pic["$\varepsilon$", draw, angle radius=3mm] {angle=w--X--a};
\end{tikzpicture}
\end{document} 