# Is there a way to draw/fill with eraser (tikz)? [duplicate]

I wish build up a tikz picture from layers. Is there a way to draw/fill one of the layer with "eraser" (not transparency)? Somehow:

I have no idea therefore neither MWE :-/

(I know, that there is an easier way to do the example document above, but that is only an example.)

• mwe is usually added to save us from the annoyance of writing those rectangle and color parts. – percusse Dec 28 '16 at 16:01
• your question is not clear. see, if the following MWE gives what you expect: \documentclass[tikz, margin=3mm]{standalone} \begin{document} \begin{tikzpicture}[ box/.style args = {#1/#2}{minimum size=#1, fill=#2, font=\Large\sffamily\bfseries} ] \node[box=44mm/green,draw] {Text}; \node[box=33mm/red] {}; \node[box=22mm/white,draw] {}; \node[box=11mm/blue] {}; \end{tikzpicture} \end{document} – Zarko Dec 28 '16 at 17:29
• What you are asking cannot be constructed by piling layers on top of each other; in effect, you want your eraser layer to cut into the layers beneath it. AFAIK that is impossible. This question discusses a possible work-around: tex.stackexchange.com/questions/336502/… – Michael Palmer Dec 28 '16 at 19:54
• Keyword: knockout group and inverse clipping – Symbol 1 Dec 29 '16 at 0:50

Instead of erasing, you could simply not draw the filling in the first place:

\documentclass{standalone}
\usepackage{tikz}

\begin{document}

\begin{tikzpicture}
\fill[green] (0,0) rectangle (1,1);
\draw[red, line width=3pt] (0.2,0.2) rectangle (0.8,0.8);
\fill[blue] (0.4,0.4) rectangle (0.6,0.6);
\end{tikzpicture}

\end{document}