I'd like to draw a right angle in a 3D-pstricks-graphic. I can't find a way to do that. This is what I want to do (but in 3D):
Here is my code:
\documentclass{standalone}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[ngerman]{babel}
\usepackage{pst-all}
\usepackage{pst-3dplot}
\begin{document}
\psset{coorType=2}
\begin{pspicture}(-3,-3.1)(3.5,3.5)
\pstThreeDCoor[xMin = -3, xMax = 3, yMin = -3, yMax = 3, zMin = -3, zMax = 3, arrows = ->, linecolor=black]
\pstThreeDTriangle[fillcolor=yellow,fillstyle=solid,linecolor=black,opacity=0.5](2,0,0)(0,2.5,0)(0,0,1)
\pstThreeDLine[linestyle=dashed](0.489361,0.691489,0.478723)(1.5,1.5,2.5)
\pstThreeDDot(1.5,1.5,2.5)
\pstThreeDPut(1.5,1.8,2.5){$P$}
\pstThreeDDot(0.489361,0.691489,0.478723)
\pstThreeDPut(0.489361,0.991489,0.478723){$P'$}
\pstThreeDDot(2,0,0)
\pstThreeDPut(2,-0.3,0){2}
\pstThreeDDot(0,2.5,0)
\pstThreeDPut(0,2.5,0.3){2.5}
\pstThreeDDot(0,0,1)
\pstThreeDPut(0,-0.3,1){1}
\end{pspicture}
\end{document}
In the picture you can see what I have got. I need to show two right angles so the projection is better visible.
Is there an equivalent of \psarc
in 3D?