4

As the question states, I want a tilde over \equiv similar to \simeq and \cong commands. To be more specific, they tilde needs to be closer to the \equiv symbol.

I've tried using stackrel and DeclareMathOperator* but they place it way too high.

I've even tried to place it under empty space over \equiv as math operator as in

\DeclareMathOperator*{\eq}{\equiv}
\newcommand{\poly}{\eq^{\stackrel{\sim}{\hspace*{2em}}}}

yet still no luck.

Any suggestions? Thanks.

5

A straightforward modification of the code for \cong in fontmath.ltx

\DeclareRobustCommand
  \cong{\mathrel{\mathpalette\@vereq\sim}} % congruence sign
\def\@vereq#1#2{\lower.5\p@\vbox{\lineskiplimit\maxdimen\lineskip-.5\p@
    \ialign{$\m@th#1\hfil##\hfil$\crcr#2\crcr=\crcr}}}

Here is the new \ccong (change the name to your liking):

\documentclass{article}

\makeatletter
\DeclareRobustCommand{\ccong}{\mathrel{\mathpalette\@verequiv\sim}}
\newcommand{\@verequiv}[2]{%
  \lower.5\p@\vbox{
    \lineskiplimit\maxdimen
    \lineskip-.5\p@
    \ialign{%
      $\m@th#1\hfil##\hfil$\crcr
      #2\crcr
      \equiv\crcr
    }%
  }%
}
\makeatother

\begin{document}

$A=B\equiv C\cong D\ccong E$

\end{document}

enter image description here

0
1

Here, I use a stack.

\documentclass{article}
\usepackage{amssymb,amsmath,stackengine}
\DeclareMathOperator*{\eq}{\equiv}
\newcommand{\poly}{\mathrel{\ensurestackMath{%
  \stackengine{-.5pt}{\equiv}{\sim}{O}{c}{F}{F}{S}}}}
\begin{document}
$A \equiv A \simeq A \cong A \poly A$
\end{document}

enter image description here

EDIT: Here is a version that works for smaller math styles

\documentclass{article}
\usepackage{amssymb,amsmath,stackengine,scalerel}
\DeclareMathOperator*{\eq}{\equiv}
\newcommand{\poly}{\mathrel{\ThisStyle{\ensurestackMath{%
  \stackengine{-.5\LMpt}{\SavedStyle\equiv}{\SavedStyle\sim}{O}{c}{F}{F}{S}}}}}
\begin{document}
$A \equiv A \simeq A \cong A \poly A$\par
$\scriptstyle A \equiv A \simeq A \cong A \poly A$\par
$\scriptscriptstyle A \equiv A \simeq A \cong A \poly A$\par
\end{document}

enter image description here

2

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.