8

I have a code like this: (I used the font mtpro2.)

\renewcommand{\arraystretch}{1.6}    
\begin{tabular}{p{8cm}l}
    \multicolumn{2}{l}{(a)~$\left( \frac{81}{16}\right)^{-0.25}\times \left( \frac{8}{27}\right) ^{-\frac{2}{3}}\times (0.25)^{-2.5}+\left(\sqrt{243\sqrt{3}}\right)^{\frac{1}{11}}\times (\sqrt{3})^{-1}=?$} \\
    (b)~$\sqrt[3]{a^{\frac{9}{2}}\sqrt{a^{-3}}}\div \sqrt{\sqrt[3]{a^{-7}}\cdot \sqrt[3]{a}}=?$ & (c)~$(5+2\sqrt{6})^{2000}\cdot (5-2\sqrt{6})^{1999}$ \\
    (d)~$\sqrt[a-b]{x^{\frac{b+c}{c-a}}}\sqrt[b-c]{x^{\frac{c+a}{a-b}}}\sqrt[c-a]{ x^{\frac{a+b}{b-c}}}=?$  &(e)~$(x^{\frac{2}{3}}+x^{-\frac{2}{3}}+1)(x^{\frac{2}{3}}-x^{-\frac{2}{3}})(x-x^{-1})^{-1}=?$
\end{tabular}

enter image description here

How can I make the superscript higher and a little bigger? For example, the orangle part in (d). I've tried throwing \displaystyle in the sub formula in \sqrt{}, but it wasn't lift up much. By the way, I use \renewcommand{\arraystretch}{1.6} to lengthen the lineskip in my tabular environment. Is my method good enough? Is there another proper way to do the same thing?

Improve this question
6
  • 1
    Is x^{(b+c)/(c-a)} an option?
    – Steven B. Segletes
    Mar 31, 2017 at 12:29
  • @Steven B. Segletes In Asia, it is rarely to write fraction like this, especially in the college textbook. So a true fraction is necessary.
    – Eric
    Mar 31, 2017 at 12:30
  • How about x^{\nicefrac{(b+c)}{c-a}} (from package nicefrac) then? (I actually use a simple macro for a similar slanted but vertically offset fraction, mainly inline).
    – Chris H
    Mar 31, 2017 at 12:32
  • @Chris H Do I need to include some package? I can't compile.
    – Eric
    Mar 31, 2017 at 12:33
  • 1
    @ChrisH Thanks. I've tested. It is a cool package. But I still need a tradition vertical fraction.
    – Eric
    Mar 31, 2017 at 12:36

2 Answers 2

Reset to default
11

While this approach does not increase the size of the superscript font, it does raise the scripted fraction, by using x\strut^{\frac{b+c}{c-a}} instead of x^{\frac{b+c}{c-a}}, which places the superscript relative to a \strut instead of an x.

\documentclass{article}

\begin{document}
\renewcommand{\arraystretch}{1.6}    
\begin{tabular}{p{8cm}l}
    \multicolumn{2}{l}{(a)~$\left( \frac{81}{16}\right)^{-0.25}\times \left( \frac{8}{27}\right) ^{-\frac{2}{3}}\times (0.25)^{-2.5}+\left(\sqrt{243\sqrt{3}}\right)^{\frac{1}{11}}\times (\sqrt{3})^{-1}=?$} \\
    (b)~$\sqrt[3]{a^{\frac{9}{2}}\sqrt{a^{-3}}}\div \sqrt{\sqrt[3]{a^{-7}}\cdot \sqrt[3]{a}}=?$ & (c)~$(5+2\sqrt{6})^{2000}\cdot (5-2\sqrt{6})^{1999}$ \\
    (d)~$\sqrt[a-b]{x\strut^{\frac{b+c}{c-a}}}\sqrt[b-c]{x\strut^{\frac{c+a}{a-b}}}\sqrt[c-a]{ x\strut^{\frac{a+b}{b-c}}}=?$  &(e)~$(x^{\frac{2}{3}}+x^{-\frac{2}{3}}+1)(x^{\frac{2}{3}}-x^{-\frac{2}{3}})(x-x^{-1})^{-1}=?$
\end{tabular}
\end{document}

enter image description here

For comparison, here it is without the \struts

enter image description here

Improve this answer
5
  • Wow. It seems to be what I want. Can you explain more on the mechanism of \strut? I mean what is this command designed for? :)
    – Eric
    Mar 31, 2017 at 12:38
  • 1
    @Eric \strut (not \struct) is a zero-width entity that vertically spans exactly one complete line height and depth. All normal text will otherwise fit within the vertical footprint of a \strut. If some stacked in-line construction exceeds the height or depth of the \strut, the document line spacing will become irregular, since room must be made to accommodate the extra height/depth. The height plus depth of a \strut equals exactly the value of \baselineskip.
    – Steven B. Segletes
    Mar 31, 2017 at 12:41
  • @Eric For someghing more visual, a \strut is a zero-width version of this: \rule[-\dp\strutbox]{1pt}{\baselineskip}. Try setting that in a line of text to see it relative to surrounding text.
    – Steven B. Segletes
    Mar 31, 2017 at 13:18
  • I'm typesetting a Chinese document, so my line spacing is big(I set \linespread{1.6}). When I use \strut in math mode, the exponent part will be lift too up. How can I modify it? (See the middle root in imgur.com/a/FsiNi)
    – Eric
    Apr 3, 2017 at 9:04
  • 1
    @Eric you can \newcommand\mystrut{\rule{0pt}{10pt}} and use \mystrut instead of \strut, while varying the height of \mystrut (here chosen as 10pt) to suit your needs. You can add depth to the strut, if needed, with the syntax \rule[<depth>]{0pt}{<height+depth>}
    – Steven B. Segletes
    Apr 3, 2017 at 10:28
3

How about just x^{^{\frac{b+c}{c-a}}}?

Improve this answer
2

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .