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table

Hello there, here is my table but I can't figure out how to arrange (x,y,z) coordinates in a good looking(i mean they are not in a straight line :) ) and also every box , they start appear center-north, for good looking, I want to center-center :) sorry for bad language. thanks advance.

Here is my code, sorry for not arranging it, I haven't get used to TeX.SE yet :)

\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}
  \hline
  Step(k) & I.strategy & II.strategy & $\,$ Return $\,$ & Total Return &$\quad$ $g_{i}^r$ $\quad$ &$\quad$ $g_{k}^c$ $\quad$ & $\,$ $U_k$ $\,$ & $\,$ $V_k$  $\,$ & $\displaystyle \frac{minU_k}{k}$ & $ \displaystyle \frac{maxV_k}{k}$ \\[2ex] \hline
   1 & $I_1$ & $II_1$ & 9 & 9 & (9,2,-1) & (9,-9,6) & (9,2,{\color{blue}-1})     & ({\color{red}9},-9,6)     & -1              & 9               \\[1.5ex] \hline
   2 & $I_1$ & $II_3$ &-1 & 8 & (9,2,-1) & (-1,0,2) & (18,4,{\color{blue}-2})    & ({\color{red}8},-9,8)     & -1              & 4               \\[1.5ex] \hline 
   3 & $I_1$ & $II_3$ &-1 & 7 & (9,2,-1) & (-1,0,2) & (27,6,{\color{blue}-3})    & (7,-9,{\color{red}10})    & -1              & $\frac{10}{3}$     \\[1.5ex] \hline
   4 & $I_3$ & $II_3$ & 2 & 9 & (6,-6,2) & (-1,0,2) & (33,0,{\color{blue}-1})    & (6,-9,{\color{red}12})    & $-\frac{1}{4}$  & $3$              \\[1.5ex] \hline
   5 & $I_3$ & $II_3$ & 2 &11 & (6,-6,2) & (-1,0,2) & (39,{\color{blue}-6},1)    & (5,-9,{\color{red}14})    & $-\frac{6}{5}$  & $\frac{14}{5}$     \\[1.5ex] \hline 
   6 & $I_3$ & $II_2$ &-6 & 5 & (6,-6,2) & (2,9,-6) & (45,{\color{blue}-12},3)   & (7,0,{\color{red}8})      & $-2$            & $\frac{4}{3}$     \\[1.5ex] \hline
   7 & $I_3$ & $II_2$ &-6 &-1 & (6,-6,2) & (2,9,-6) & (51,{\color{blue}-18},5)   & ({\color{red}9},9,2)      & $-\frac{18}{7}$ & $\frac{9}{7}$     \\[1.5ex] \hline
   8 & $I_1$ & $II_2$ & 2 & 1 & (9,2,-1) & (2,9,-6) & (60,{\color{blue}-16},4)   & (11,{\color{red}18},-4)   & $-2$            & $\frac{9}{4}$     \\[1.5ex] \hline 
   9 & $I_2$ & $II_2$ & 9 &10 & (-9,9,0) & (2,9,-6) & (51,{\color{blue}-7},4)    & (13,{\color{red}17},-10)  & $-\frac{7}{9}$  & $\frac{17}{9}$     \\[1.5ex] \hline
  10 & $I_2$ & $II_2$ & 9 &19 & (-9,9,0) & (2,9,-6) & (42,{\color{blue}2},4)     & (15,{\color{red}26},-16)  & $\frac{1}{5}$   & $\frac{13}{5}$     \\[1.5ex] \hline 
  11 & $I_2$ & $II_2$ & 9 &28 & (-9,9,0) & (2,9,-6) & (33,11,{\color{blue}4})    & (17,{\color{red}35},-22)  & $\frac{4}{11}$  & $\frac{35}{11}$     \\[1.5ex] \hline
  12 & $I_2$ & $II_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (24,20,{\color{blue}4})    & (16,{\color{red}35},-20)  & $\frac{1}{3}$   & $\frac{35}{12}$     \\[1.5ex] \hline 
  13 & $I_2$ & $II_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (15,29,{\color{blue}4})    & (15,{\color{red}35},-18)  & $\frac{4}{13}$  & $\frac{35}{13}$     \\[1.5ex] \hline
  14 & $I_2$ & $II_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (6,38,{\color{blue}4})     & (14,{\color{red}35},-16)  & $\frac{4}{14}$  & $\frac{35}{14}$     \\[1.5ex] \hline
  15 & $I_2$ & $II_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & ({\color{blue}-3},47,4)    & (13,{\color{red}35},-14)  & $-\frac{3}{5}$  & $\frac{7}{3}$     \\[1.5ex] \hline
\end{tabular}
6
  • Can you please add some code?
    – egreg
    Commented Apr 8, 2017 at 11:11
  • Please, show code by which you produce your table in form of small, complete document, which we can compile in out computers. Help us to help you!
    – Zarko
    Commented Apr 8, 2017 at 11:11
  • @Zarko editted.
    – Alper
    Commented Apr 8, 2017 at 11:15
  • @egreg i editted the post :)
    – Alper
    Commented Apr 8, 2017 at 11:26
  • 1
    @AlperErdem, if sone else not answer before, I will give closet look late evening (GMT). In the first sight, table is huge and I cant believe, that it can be fit in text width. Otherwise, to align coordinates in line, you need to write each coordinate in separate column (with zero \tabcolsep). Also use of S column type from siunitx package would help.
    – Zarko
    Commented Apr 8, 2017 at 11:26

1 Answer 1

1

I suggest a more open look to the table and also some tricks for simplifying the input.

However, I believe that the slashed form 10/3 would render better than \frac{10}{3}.

\documentclass{article}
\usepackage[landscape,a4paper]{geometry}
\usepackage{array,booktabs}
\usepackage{amsmath}
\usepackage{xcolor}

\newcommand{\bn}[1]{% blue number
  \textcolor{blue}{#1}%
}
\newcommand{\rn}[1]{% red number
  \textcolor{red}{#1}%
}

\begin{document}

\begin{table}
\centering

\renewcommand{\arraystretch}{1.2}
\addtolength{\tabcolsep}{-.2pt}

\begin{tabular}{
  *{3}{c}
  *{8}{>{$}c<{$}}
}
\toprule
Step($k$) &
  Strategy I &
  Strategy II &
  \multicolumn{1}{c}{Return} &
  \multicolumn{1}{c}{Total Return} &
  g_{i}^r &
  g_{k}^c &
  U_k &
  V_k &
  \dfrac{\min U_k}{k} &
  \dfrac{\max V_k}{k} \\
\midrule
   1 & I$_1$ & II$_1$ & 9 & 9 & (9,2,-1) & (9,-9,6) & (9,2,\bn{-1})     & (\rn{9},-9,6)     & -1              & 9               \\
   2 & I$_1$ & II$_3$ &-1 & 8 & (9,2,-1) & (-1,0,2) & (18,4,\bn{-2})    & (\rn{8},-9,8)     & -1              & 4               \\ 
   3 & I$_1$ & II$_3$ &-1 & 7 & (9,2,-1) & (-1,0,2) & (27,6,\bn{-3})    & (7,-9,\rn{10})    & -1              & \frac{10}{3}     \\
   4 & I$_3$ & II$_3$ & 2 & 9 & (6,-6,2) & (-1,0,2) & (33,0,\bn{-1})    & (6,-9,\rn{12})    & -\frac{1}{4}  & 3              \\
   5 & I$_3$ & II$_3$ & 2 &11 & (6,-6,2) & (-1,0,2) & (39,\bn{-6},1)    & (5,-9,\rn{14})    & -\frac{6}{5}  & \frac{14}{5}     \\ 
   6 & I$_3$ & II$_2$ &-6 & 5 & (6,-6,2) & (2,9,-6) & (45,\bn{-12},3)   & (7,0,\rn{8})      & -2            & \frac{4}{3}     \\
   7 & I$_3$ & II$_2$ &-6 &-1 & (6,-6,2) & (2,9,-6) & (51,\bn{-18},5)   & (\rn{9},9,2)      & -\frac{18}{7} & \frac{9}{7}     \\
   8 & I$_1$ & II$_2$ & 2 & 1 & (9,2,-1) & (2,9,-6) & (60,\bn{-16},4)   & (11,\rn{18},-4)   & -2            & \frac{9}{4}     \\ 
   9 & I$_2$ & II$_2$ & 9 &10 & (-9,9,0) & (2,9,-6) & (51,\bn{-7},4)    & (13,\rn{17},-10)  & -\frac{7}{9}  & \frac{17}{9}     \\
  10 & I$_2$ & II$_2$ & 9 &19 & (-9,9,0) & (2,9,-6) & (42,\bn{2},4)     & (15,\rn{26},-16)  & \frac{1}{5}   & \frac{13}{5}     \\ 
  11 & I$_2$ & II$_2$ & 9 &28 & (-9,9,0) & (2,9,-6) & (33,11,\bn{4})    & (17,\rn{35},-22)  & \frac{4}{11}  & \frac{35}{11}     \\
  12 & I$_2$ & II$_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (24,20,\bn{4})    & (16,\rn{35},-20)  & \frac{1}{3}   & \frac{35}{12}     \\
  13 & I$_2$ & II$_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (15,29,\bn{4})    & (15,\rn{35},-18)  & \frac{4}{13}  & \frac{35}{13}     \\
  14 & I$_2$ & II$_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (6,38,\bn{4})     & (14,\rn{35},-16)  & \frac{4}{14}  & \frac{35}{14}     \\
  15 & I$_2$ & II$_3$ & 0 &28 & (-9,9,0) & (-1,0,2) & (\bn{-3},47,4)    & (13,\rn{35},-14)  & -\frac{3}{5}  & \frac{7}{3}     \\
\bottomrule
\end{tabular}

\end{table}

\end{document}

enter image description here

2
  • thank you @egreg it was very useful for me , you are lifesaver :) i have one last thing to figure out, when i use ` \usepackage{fancyhdr} \pagestyle{fancy} \lhead{head1} \rhead{head2} on the page meaningless a word "draft " appears. how can i get rid of it ?
    – Alper
    Commented Apr 8, 2017 at 17:22
  • @AlperErdem That is another question, ask a separate one, please!
    – CarLaTeX
    Commented Apr 9, 2017 at 6:36

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