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I don't know what to do in order to fit this equation in the document, because it's so long. Help will be very appreciated, and also if someone have any idea how to simplify this equation it's will be very helpful. 

\documentclass[12pt]{article}
\begin{document}
\begin{equation} a(t) =
\frac{6.67384\times 10^{-11}\times 5.972\times 10^{24}}
{ \left[149.6\sin (\frac{3\pi t}{47\times 10^6})-0.908
\left( 2.5\times 10^{-8} t^2 + 9.479 \times 10^{-6}(t+
\left| t-379.189\right| -379.189)\right)\right]^2+
\left[149.638 - 0.418(2.5\times 10^{-8} t^2 + 9.479
\times 10^{-6}(t+\left| t-379.189\right| -379.189))- 149.6 \cos
\left( \frac{3\pi t}{47\times 10^6}
\right)\right]^2+ 0.0002831}
\end{equation}
\end{document}
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9
  • 2
    Your question leaves all the effort to our community, even typing the essentials of a TeX document such as \documentclass{}...\begin{document} etc. As it is, most of our users will be very reluctant to touch your question, and you are left to the mercy of our procrastination team who are very few in number and very picky about selecting questions. You can improve your question by adding a minimal working example (MWE) that more users can copy/paste onto their systems to work on. If no hero takes the challenge we might have to close your question.
    – Teepeemm
    May 19, 2017 at 19:00
  • 1
    Your equation doesn't compile (even before I edited its presentation)
    – Steven B. Segletes
    May 19, 2017 at 19:04
  • There are single left or right delimiters, so it can't compile
    – Bernard
    May 19, 2017 at 19:08
  • I'm sorry, it's my first time posting a quastion here, I didn't know I need to add the essentials of a TeX document. Here is the new version with all of the essentials:
    – Michael Novak
    May 19, 2017 at 19:48
  • \documentclass[12pt]{article} \begin{document} \begin{equation} a(t) = \frac{6.67384\times 10^{-11}\times 5.972\times 10^{24}}{ \left[149.6\sin (\frac{3\pi t}{47\times 10^6)-0.908 \left( 2.5\times 10^{-8} t^2 + 9.479 \times 10^{-6}(t+\left| t-379.189\right| -379.189)\right)\right]^2+ \left[149.638 - 0.418(2.5\times 10^{-8} t^2 + 9.479 \times 10^{-6}(t+\left| t-379.189\right| -379.189))- 149.6 \cos \left( \frac{3\pi t}{47\times 10^6} \right)\right]^2+ 0.0002831} \end{equation}\end{document}
    – Michael Novak
    May 19, 2017 at 19:53

2 Answers 2

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1

How about

enter image description here

(You are obviously free to come up with snazzier symbols than "B", "C", and "D".)

\documentclass[12pt]{article}
\usepackage{mathtools}
\begin{document}
Let
\begin{equation} 
a(t) =
\frac{6.67384\cdot 10^{-11}\cdot 5.972\cdot 10^{24}}{B}
\end{equation}
where
\begin{align*}
B&= \bigl[149.6\sin C-0.908D \bigr]^2\\
&\quad+ \bigl[149.638 - 0.418D- 149.6 \cos C\bigr]^2 + 0.0002831\,,\\
C &= 3\pi t/(47\cdot 10^6)
\shortintertext{and}
D &= 2.5\cdot 10^{-8} t^2 + 9.479 \cdot 10^{-6}\bigl(t+
\lvert t-379.189\rvert -379.189\bigr)
\end{align*}
\end{document}
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0
1

You ask about the typeset result but the input generates errors (which means usually the pdf is not worth looking at except possibly for debugging)

Runaway argument?
{ \left [149.6\sin (\frac {3\pi t}{47\times 10^6)-0.908 \left ( 2.5\times \ETC.
! File ended while scanning use of \frac.

Which means that you have a missing }

having fixed that, it's simply too wide to read, I'd do something like the following although you may choose different subterms to pull out depending on any aspect you want to highlight,

enter image description here

\documentclass[12pt]{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
a(t) =
\frac{6.67384\times 10^{-11}\times 5.972\times 10^{24}}
{149.6\sin (\alpha)}
\end{equation}
where
\begin{align*}
\alpha&=\frac{3\pi t}{\beta}\\
\beta&=47\times 10^6-0.908
( 2.5\times 10^{-8} t^2 +\\
&\qquad 9.479 \times 10^{-6}(t+
| t-379.189| -379.189))]^2+\\
&\qquad [149.638 - 0.418(2.5\times 10^{-8} t^2 + \\
&\qquad 9.479
\times 10^{-6}(t+|t-379.189| -379.189))- \\
&\qquad 149.6 \cos
( \frac{3\pi t}{47\times 10^6})]^2+ 0.0002831
\end{align*}
\end{document}
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1
  • I think I fixed it now, but it's different than what you wrote.
    – Michael Novak
    May 19, 2017 at 21:08

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