1

I am having the following equation as below

\begin{equation}\label{eq:36}
\emph{$SINR^{D,UL}_{k,n}$} =  \frac{p_{k,n} |h_{k,n}|^2}{\sum_{m=1}^{M} \omega_{n,m}p_{m,n}|h^{C}_{m,n}|^2   + \sum_{c^{'}=1}^{C^{'}} \sum_{m^{'}}^{M^{'}} \omega^{'}_{n,m^{'},c^{'}}p_{m^{'},n}|h^{C}_{m^{'},n,k,c^{'}}|^2   + \sum_{c^{'}=1}^{C^{'}} \sum_{k^{'}}^{K^{'}} \zeta^{'}_{n,k^{'},c^{'}}p_{k^{'},n}|h^{D}_{k^{'},n,k,c^{'}}|^2  + N_{0}B}  
\end{equation}

The equation does not very well fit on one line. How can I separate this over two or three lines? Please see my figure example.

Thanks a lot.

enter image description here

4

Perhaps use multline?

\documentclass{article}
\usepackage{amsmath}
\newcommand\abs[1]{\lvert#1\rvert}
\begin{document}

\begin{multline}
  \label{eq:36}
  \mathrm{SINR}^{D,UL}_{k,n} =  p_{k,n} \abs{h_{k,n}}^2
  \biggl(
  \sum_{m=1}^{M} \omega_{n,m} p_{m,n} \abs{h^{C}_{m,n}}^2 \\
  + \sum_{c'=1}^{C'} \sum_{m'}^{M'} \omega'_{n,m',c'} p_{m',n} \abs{h^{C}_{m',n,k,c'}}^2 \\
  + \sum_{c'=1}^{C'} \sum_{k'}^{K'} \zeta'_{n,k',c'} p_{k',n} \abs{h^{D}_{k',n,k,c'}}^2
  + N_{0}B
  \biggr)^{\!-1}
\end{multline}

\end{document}

enter image description here

Or introduce aliases:

\documentclass{article}
\usepackage{amsmath}
\newcommand\abs[1]{\lvert#1\rvert}
\begin{document}

\begin{equation}
  \label{eq:36}
  \mathrm{SINR}^{D,UL}_{k,n} =  \frac{p_{k,n} \abs{h_{k,n}}^2}{X + Y + Z + N_{0}B}
\end{equation}
where
\begin{align*}
  X &= \sum_{m=1}^{M} \omega_{n,m} p_{m,n} \abs{h^{C}_{m,n}}^2 \\
  Y &= \sum_{c'=1}^{C'} \sum_{m'}^{M'} \omega'_{n,m',c'} p_{m',n} \abs{h^{C}_{m',n,k,c'}}^2 \\
  Z &= \sum_{c'=1}^{C'} \sum_{k'}^{K'} \zeta'_{n,k',c'} p_{k',n} \abs{h^{D}_{k',n,k,c'}}^2
\end{align*}

\end{document}

enter image description here

You can also make that nasty thing you showed in the question, but I do not recommend that.

\documentclass{article}
\usepackage{amsmath}
\newcommand\abs[1]{\lvert#1\rvert}
\begin{document}

\begin{equation}
  \label{eq:36}
  \mathrm{SINR}^{D,UL}_{k,n} =  \frac{p_{k,n} \abs{h_{k,n}}^2}{
    \begin{pmatrix}
      \sum_{m=1}^{M} \omega_{n,m} p_{m,n} \abs{h^{C}_{m,n}}^2 + {} \\
      \sum_{c'=1}^{C'} \sum_{m'}^{M'} \omega'_{n,m',c'} p_{m',n} \abs{h^{C}_{m',n,k,c'}}^2 + {} \\
      \sum_{c'=1}^{C'} \sum_{k'}^{K'} \zeta'_{n,k',c'} p_{k',n} \abs{h^{D}_{k',n,k,c'}}^2 + N_{0}B
    \end{pmatrix}
  }
\end{equation}

\end{document}

enter image description here

  • Great! I like the last one example as you suggested. Thanks a lot to @Henri Menke – user3727281 May 22 '17 at 21:58
  • Mmmhh… :-( \substack is meant for super/subscripts, and for this reason it typesets its argument in \scriptstyle; note that this entails that you get no space around binary operators and relation symbols. What about a pmatrix environment, instead? It usesn\textstyle, which seems much more appropriate… Also, I guess you didn’t notice the ^{'} idiom that the OP uses repeatedly, |...| instead of \lvert ... \rvert, or better, \DeclarePairedDelimiter – GuM May 22 '17 at 23:16
  • @user3727281 Why are you picking the garbage solution when I presented two other perfectly reasonable ones? – Henri Menke May 22 '17 at 23:23
  • @GustavoMezzetti You are right. I didn't put too much effort into it. Using pmatrix instead of \substack is a good. I wouldn't say a substack is completely wrong here because somehow you need to cramp all that stuff in the denominator but then this part is ugly anyway and cannot be made looking decent. – Henri Menke May 22 '17 at 23:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.