1

As the title suggests, is there a way to adjust the width of the integral symbol by compressing it in the horizontal direction? Adjustbox only seems to allow me to adjust the height, and the width does not change.

  • Member of over one year, 22 posts and no minimal working example (MWE)? -1 – Henri Menke Jun 8 '17 at 2:52
  • Are you trying to save space or make it look different? A little negative space before and after to givene things up might work better if it's just a space issue – Chris H Jun 8 '17 at 7:22
3

Use \resizebox.

\documentclass{article}
\usepackage{graphicx}
\begin{document}
$\displaystyle\int$
\resizebox{.5\width}{\height}{$\displaystyle\int$}
$\displaystyle\int$
\end{document}

enter image description here

or use an upright integral symbol which is naturally narrower, e.g. from eulervm.

\documentclass{article}
\DeclareSymbolFont{eulargesymbols}{U}{zeuex}{m}{n}
\DeclareMathSymbol{\intop}{\mathop}{eulargesymbols}{"52}
\begin{document}
$\displaystyle\int$
\end{document}

enter image description here

  • 1
    +1 for your alternative solution. The change in the weight of the (near) vertical stroke in the first option doesn't look nice. – Chris H Jun 8 '17 at 7:21
1

Here I use scalerel package's \hstretch to compress the sign to 80, 60, and 40%, respectively. Unlike \resizebox, it automatically works across math styles. I have embodied it here as \varint[<scale>].

\documentclass{article}
\usepackage{scalerel}
\newcommand\varint[1][.8]{\mathrel{\hstretch{#1}{\int}}}
\begin{document}
\[
\int_0^x \varint_{\!\!\!0}^x \varint[.6]_{\!\!0}^x  \varint[.4]_{\!0}^x 
\]
\[
\scriptstyle \int \varint \varint[.6] \varint[.4]
\]
\end{document}

enter image description here

See this related question, Integral Sign $\int...$, for integral signs that are naturally more vertical and less slanted; in the Russian style, as it were.

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