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This question is related to a question I'd asked earlier on this thread:

Drawing a Cayley tree

I have some for loops creating a graph and I'd like to position a node OVER another node whose co-ordinates I don't know.

For instance, let's say the for loop generates a node at (1.35, 0.8). I'd like to place another node at those co-ordinates, masking the original node there. These are rather odd co-ordinates that I can only find by trial and error and is rather tedious. Is there a way to position a node using something along the lines of

\node[disc] at (c-1-1) {};

where disc is some pre-specified shape and (c-1-1) is the node at (1.35,0.8) that I'd like to mask?

Apologies if this has already been asked. I searched for how to position a node using another node's label on Google and every response was how to position a node label.

Thanks

  • I assume you're using the accepted answer from that other question. If you try \node[circle,fill=blue] at (c-1-1) {}; you'll see that it works perfectly fine. For some reason though the disc style defined in that answer doesn't work after the loop, I don't know why. Note though that that style takes an argument, i.e. it should be used as disc=namefornode. – Torbjørn T. Aug 12 '17 at 21:34
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    \path (c-1-1) node[disc=b]; works. – Torbjørn T. Aug 12 '17 at 21:48
  • Thank you, that works! Yes I did use the accepted answer from that question. – WiFO215 Aug 12 '17 at 22:29
  • @TorbjørnT. My disc style requires an argument and defines a node without content: it uses an empty node contents option. – Paul Gaborit Aug 12 '17 at 22:50
  • @PaulGaborit Yes, I realized that eventually. – Torbjørn T. Aug 12 '17 at 22:51
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I'm just posting this separately here so that I can mark this thread answered.

Torbjørn T.'s answer works.

\path (c-1-1) node[disc=b];

Thank you!

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