0

In this MWE

\documentclass[a4paper]{article}

\usepackage[hmargin={2cm,2cm},vmargin={2cm,2cm}]{geometry}
\usepackage[utf8]{inputenc}
\usepackage{amsmath, amssymb}
\usepackage[french]{babel}
\usepackage[shortlabels]{enumitem}
\usepackage{multicol}

\usepackage{pgf,tikz}
\usepackage{mathrsfs}
\usetikzlibrary{arrows}



\begin{document}

\begin{enumerate}[a)]
\begin{multicols}{2}
\item La fonction $f$ est déjà sous forme canonique. On reconnaît $\alpha = -1$ et $\beta = 3$. De plus, le coefficient dominant de $f$ est $-2>0$. Donc, la courbe $\mathscr{C}_f$ de $f$ est une parabole tournée vers le bas et de sommet $(-1,3)$.

On calcule de plus : $f(0)=1$. Cela nous permet de dessiner : 
\columnbreak

\definecolor{sexdts}{rgb}{0.1803921568627451,0.49019607843137253,0.19607843137254902}\definecolor{cqcqcq}{rgb}{0.7529411764705882,0.7529411764705882,0.7529411764705882}\begin{tikzpicture}[line cap=round,line join=round,>=triangle 45,x=1cm,y=1cm]\draw [color=cqcqcq,, xstep=1cm,ystep=1cm] (-3.63555555555557,-2.45) grid (2.3022222222221753,4.474444444444443);\draw[->,color=black] (-3.63555555555557,0) -- (2.3022222222221753,0);\foreach \x in {-3,-2,-1,1,2}\draw[shift={(\x,0)},color=black] (0pt,2pt) -- (0pt,-2pt) node[below] {\footnotesize $\x$};\draw[->,color=black] (0,-2.45) -- (0,4.474444444444443);\foreach \y in {-2,-1,1,2,3,4}\draw[shift={(0,\y)},color=black] (2pt,0pt) -- (-2pt,0pt) node[left] {\footnotesize $\y$};\draw[color=black] (0pt,-10pt) node[right] {\footnotesize $0$};\clip(-3.63555555555557,-2.45) rectangle (2.3022222222221753,4.474444444444443);\draw[line width=2pt,color=sexdts,smooth,samples=100,domain=-3.63555555555557:2.3022222222221753] plot(\x,{0-2*((\x)+1)^(2)+3});\end{tikzpicture}
\end{multicols}

\end{enumerate}

\end{document}

enter image description here

the first column is vertically justified. I would like to have a normal vertical spacing in this first column.

Is it possible to break a column but without vertically justifying the broken column?

2

Just before \columnbreak insert \vfill\mbox{} I don't know if it always works, but works with your MWE.

  • it should work generally in such a context – Frank Mittelbach Oct 5 '17 at 6:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.