# How to draw this diagram in tikz?

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• Because of the regular layout, you might want to use the matrix tikzlibrary. You still need to draw all the connecting lines, but each node will automatically be given a name like A-1-1 for [name=A]. – John Kormylo Oct 7 '17 at 14:25

Just as exercise:

\documentclass[border=1cm]{standalone}
\usepackage{tikz}
\usetikzlibrary{matrix}
\usetikzlibrary{positioning, calc, arrows.meta}
\tikzset{
mynode/.style={draw=red, rounded corners, thick},
myredline/.style={draw=red, thick},
}

\begin{document}
\begin{tikzpicture}
\matrix[
matrix of nodes,
column sep=6em,
nodes in empty cells,
nodes={
text centered,
text width=6em,
text height=1.75ex,
text depth=.25ex,
},
] (m) {
100\% & |[mynode]|Next Coupon & |[mynode]|\dots & |[mynode]|100\% + \dots \\[5ex]
0 & & \dots & \dots \\
LCD & NCD && \\
};
\foreach \pos in {1,2,3,4}{
\draw (m-1-\pos) -- (m-2-\pos);
}
\foreach \pos in {2,3,4}{
\draw[myredline] (m-1-\pos) -- +(0,4ex);
}
\draw ($(m-1-1)!0.5!(m-2-1)$) -- ($(m-1-4)!0.5!(m-2-4)$);
\draw[myredline] ($(m-1-4)+(0,4ex)$) -- node[red, above] {Atualiza\c c\~ao} ($(m-1-2)+(0,4ex)$);
\coordinate (between1and2) at ($(m-1-1)!0.5!(m-1-2)$);
\draw[myredline, -Latex] ($(m-1-2)+(0,4ex)$) -- ($(between1and2)+(0,4ex)$) -- (between1and2) -- (m-1-1);
\end{tikzpicture}
\end{document}