I'm trying to create the circuit shown in the picture using the circuitikz
package, but I just can't find any similar example to array the elements in that way. Can someone help me with the code?
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Could you at least try first? There are far more complicated examples here.– John KormyloNov 29, 2017 at 4:07
1 Answer
Since this is a do-it-for-me question, this is just a practice for me and I will not be entertaining further questions regarding this.
\documentclass{article}
\usepackage[dvipsnames]{xcolor}
\usepackage[american,siunitx]{circuitikz}
\usetikzlibrary{arrows.meta}
% Ref: https://tex.stackexchange.com/a/396801/117534
\makeatletter
\ctikzset{current arrow color/.initial=black}% create key
\pgfdeclareshape{currarrow}{
\anchor{center}{
\pgfpointorigin
}
\anchor{tip}{
\pgfpointorigin
\pgf@circ@res@step = \pgf@circ@Rlen
\divide \pgf@circ@res@step by 16
\pgf@x =\pgf@circ@res@step
}
\behindforegroundpath{
\pgfscope
\pgf@circ@res@step = \pgf@circ@Rlen
\divide \pgf@circ@res@step by 16
\pgfpathmoveto{\pgfpoint{-.7\pgf@circ@res@step}{0pt}}
\pgfpathlineto{\pgfpoint{-.7\pgf@circ@res@step}{-.8\pgf@circ@res@step}}
\pgfpathlineto{\pgfpoint{1\pgf@circ@res@step}{0pt}}
\pgfpathlineto{\pgfpoint{-.7\pgf@circ@res@step}{.8\pgf@circ@res@step}}
\pgfpathlineto{\pgfpoint{-.7\pgf@circ@res@step}{0pt}}
\pgfsetcolor{\pgfkeysvalueof{/tikz/circuitikz/current arrow color}}
\pgfusepath{fill,draw}
\endpgfscope
}
}
\makeatother
\begin{document}
\begin{circuitikz}[color=NavyBlue]
\draw[circuitikz/current arrow color=red]
(0,0) to[R=20<\ohm>] (2,0) to[battery1, l=10<\volt>,i_=$I_3$] (4,0)
-- (4,1.8) to[battery1,l_=10<\volt>, i^<=$I_2$] (2,1.8) to[R, l_=5<\ohm>] (0,1.8) -| (0,0)
-| (0,3.6) to[R=10<\ohm>] (2,3.6) to[battery1, l=6<\volt>,i_=$I_1$] (4,3.6) -- (4,1.8)
;
\end{circuitikz}
\end{document}
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Thank you very much for your time and sorry for asking too much and not trying Dec 9, 2017 at 3:51