Pgfplotstable - Using conditional statement in assign column name

Question

I'm currently loading a table via '\pgfplotstabletypeset` and I found out that I can manipulate the header like this:

\documentclass{article}
\usepackage{pgfplotstable}
\usepackage{filecontents}

\begin{filecontents*}{data.csv}
    a b c d
    1 4 5 1
    2 3 1 5
    3 5 6 1
    4 1 4 9
    5 3 4 7
\end{filecontents*}

\begin{document}
    \pgfplotstabletypeset[
        assign column name/.style= {%
            /pgfplots/table/column name={#1 $\left[\frac{1}{\textrm{s}}\right]$}
        },
    ] {data.csv}
\end{document}

Now I have come to a point where I only want to change the column names of columns > 0 (so the first one should stay just the way it is). However all my attempts to create a conditional statement that uses \pgfplotstablecol in order to retrieve the column index have failed.

What I want is something like this: \documentclass{article} \usepackage{pgfplotstable} \usepackage{filecontents}

\begin{filecontents*}{data.csv}
    a b c d
    1 4 5 1
    2 3 1 5
    3 5 6 1
    4 1 4 9
    5 3 4 7
\end{filecontents*}

\begin{document}
    \pgfplotstabletypeset[
        assign column name/.style= {%
            if first column -> /pgfplots/table/column name={#1}
            else -> /pgfplots/table/column name={#1 $\left[\frac{1}{\textrm{s}}\right]$}
        },
    ] {data.csv}
\end{document}

What is the proper way to tackle this problem?

Answer 1

Using an own counter the solution is rather simple:

\documentclass{article}
\usepackage{pgfplotstable}
\usepackage{filecontents}

\begin{filecontents*}{data.csv}
    a b c d
    1 4 5 1
    2 3 1 5
    3 5 6 1
    4 1 4 9
    5 3 4 7
\end{filecontents*}

\newcount\Ravenfoo

\begin{document}
\pgfplotstabletypeset[
  assign column name/.style = {%
    /pgfplots/table/column name = {
      \ifnum\Ravenfoo>0%
          #1 $\left[\frac{1}{\textrm{s}}\right]$
      \else
        \global\advance\Ravenfoo by 1\relax
        #1
      \fi%
    }
  },
] {data.csv}
\end{document}