TikZ - Game theory tree with continuum of moves (depicted as a gray triangle)

In extensive form games (game trees), we usually draw a (gray) triangle in the background of the player's branch (strategy) to denote that the player has a continuum of actions available at that node. For example, in the game tree I am sending below I manually draw the triangles for player PM. Player PM has to choose an x (that can assume any value from 0 to 1). However, I don't know how to draw the triangles using TikZ in LaTeX. I am sending what I am looking for: Below, I am sending the TikZ code I wrote to produce my tree (without the triangles, of course):

\documentclass{article}
\usepackage{sgame, tikz} % Game theory packages
\usetikzlibrary{trees,backgrounds,calc,positioning,arrows}
\begin{document}
\begin{tikzpicture}[scale=2.5,font=\footnotesize]
\tikzset{
% Two node styles for game trees: solid and hollow
solid node/.style={circle,draw,inner sep=1.5,fill=black},
hollow node/.style={circle,draw,inner sep=1.5}
}
% Specify spacing for each level of the tree
\tikzstyle{level 1}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 2}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 3}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 4}=[level distance=8mm,sibling distance=20mm]
\tikzstyle arrowstyle=[scale=2.5]
\tikzstyle directed=[postaction={decorate,decoration={markings,
mark=at position .5 with {\arrow[arrowstyle]{stealth}}}}]
% The Tree
\node(0)[hollow node,label=above:{$PM$}]{}
child{node(2)[solid node,label=right:{$l_{i}$}]{}
child{node(3)[hollow node,label=left:{$PM$}]{}
child { node [solid node, label=left:$l_{i}$] {}
child {
node {\emph{x}}
edge from parent
node[left, xshift=-3] {$Y$}}
child { node [solid node, label=right:$l_{i}$] {}
child { node [solid node,label=right:$l_{i}$] {}
child {
node {\emph{ne}}
edge from parent
node[left, xshift=-3] {$A$}}
child {
node {$\ddots$}
edge from parent
node[right, xshift=3] {$\neg A$}}
edge from parent
node[right] {}
edge from parent
node[left] {$VNC$}}
child {
node {$\ddots$}
edge from parent
node[right] {$\neg VNC$}}
edge from parent
node[right] {}
edge from parent
node[right, xshift=2] {$N$}}
edge from parent
node[right] {$x$}}
edge from parent node[left, xshift=-3]{$A$}}
child{node(4)[label=below:{$SQ$}]{}
edge from parent node[right]{$\neg A$}
}
edge from parent node[right,xshift=3]{$p$}
};
\end{tikzpicture}
\end{document}
• Please make your code compilable. – cfr Feb 8 '18 at 4:08

I would probably add the triangles in the background layer. To this end, I load the library backgrounds (and calc for coordinate mending).

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{backgrounds,calc}
\begin{document}
\begin{tikzpicture}[scale=2.5,font=\footnotesize]
\tikzset{
% Two node styles for game trees: solid and hollow
solid node/.style={circle,draw,inner sep=1.5,fill=black},
hollow node/.style={circle,draw,inner sep=1.5}
}
% Specify spacing for each level of the tree
\tikzstyle{level 1}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 2}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 3}=[level distance=8mm,sibling distance=20mm]
\tikzstyle{level 4}=[level distance=8mm,sibling distance=20mm]
\tikzstyle arrowstyle=[scale=2.5]
\tikzstyle directed=[postaction={decorate,decoration={markings,
mark=at position .5 with {\arrow[arrowstyle]{stealth}}}}]
% The Tree
\node(0)[hollow node,label=above:{$PM$}]{}
child{node(2)[solid node,label=right:{$l_{i}$}]{}
child{node[hollow node,label=left:{$PM$}](3){}
child { node[solid node, label=left:$l_{i}$](5) {}
child {
node{\emph{x}}
edge from parent
node[left, xshift=-3] {$Y$}}
child { node [solid node, label=right:$l_{i}$] {}
child { node [solid node,label=right:$l_{i}$] {}
child {
node {\emph{ne}}
edge from parent
node[left, xshift=-3] {$A$}}
child {
node {$\ddots$}
edge from parent
node[right, xshift=3] {$\neg A$}}
edge from parent
node[right] {}
edge from parent
node[left] {$VNC$}}
child {
node {$\ddots$}
edge from parent
node[right] {$\neg VNC$}}
edge from parent
node[right] {}
edge from parent
node[right, xshift=2] {$N$}}
edge from parent
node[right] {$x$}}
edge from parent node[left, xshift=-3]{$A$}}
child{node(4)[label=below:{$SQ$}]{}
edge from parent node[right]{$\neg A$}
}
edge from parent node[right,xshift=3]{$p$}
};
\begin{scope}[on background layer]
\draw[fill=gray!40](0.south)--($(2)+(0.6cm,0)$)--($(2)-(0.6cm,0)$)--cycle;
\draw[fill=gray!40](3.south)--($(5)+(0.6cm,0)$)--($(5)-(0.6cm,0)$)--cycle;
\end{scope}
\end{tikzpicture}
\end{document} • is it possible to draw the triangles with no (black) borders? – Thiago Feb 8 '18 at 4:18
• @Thiago Sure, just replace \draw by \fill in the commands inside the scope. – user121799 Feb 8 '18 at 4:21

Well, Forest would be easier if you have to draw several. For example, your tree could be specified as follows:

\begin{forest}
dec tree,
[PM
[l_i, my label=p, cont
[PM, my label=A
[l_i, my label=x, cont
[x, my label=Y]
[l_i, my label=N
[l_i, my label=VNC
[ne, my label=A]
[, my label=\lnot A]
]
[, my label=\lnot VNC]
]
]
]
[Sq, my label=\lnot A]
]
]
\end{forest}

where my label sets up the edge labels, dec tree enables the overall style, and cont sets a triangle for the parent of the current node. You can tweak this as desired. (For example, you probably want cont to be specified for the parent and not one of the children. I did it this way only because I initially thought of making it the child's edge.)

\documentclass[border=10pt]{standalone}
\usepackage{forest}
\forestset{
declare toks={lpost}{left},
my label/.style={
if n=1{
edge label={node [midway, left] {$#1$}}
}{
edge label={node [midway, right] {$#1$}}
},
},
cont/.style={
tikz+={
\fill [fill=black, fill opacity=.5, blend mode=darken] (!u.children) -- ([xshift=25pt].center) -- ([xshift=-25pt].center) -- cycle;
},
},
dec tree/.style={
for tree={
circle,
inner sep=1.5pt,
l sep'+=25pt,
s sep'+=25pt,
calign=fixed edge angles,
},
where n children=1{draw, fill=white}{
if n children=2{draw, fill=black}{},
},
where level=0{lpost=above}{
if n'=1{lpost=right}{},
},
before typesetting nodes={
where content={}{content=\ddots, inner ysep=0pt, child anchor=parent first, math content}{
label/.process={ OOw2{content}{lpost}{##2:$##1$} },
delay={content=},
},
}
}
}
\begin{document}
\begin{forest}
dec tree,
[PM
[l_i, my label=p, cont
[PM, my label=A
[l_i, my label=x, cont
[x, my label=Y]
[l_i, my label=N
[l_i, my label=VNC
[ne, my label=A]
[, my label=\lnot A]
]
[, my label=\lnot VNC]
]
]
]
[Sq, my label=\lnot A]
]
]
\end{forest}
\end{document}

Edit: istgame version 2.0

With the istgame version 2, you can use a new macro \istrootcntm (instead of using \istcntm and \istroot) to draw a continuum of branches. Using \istrootcntm is simpler and more powerful than using \istcntm (discouraged to use the obsolete macro \istcntm). See also the use of input mode changer \setistmathTF. \documentclass{standalone}
\usepackage{istgame}
\begin{document}

\begin{istgame}[scale=2.5,font=\footnotesize]
\setistmathTF111 % all labels are in math mode
\xtdistance{8mm}{20mm}
\istrootcntm(0)[initial node]{PM}+8mm..12mm+
\istb{p}[r]
\endist
\istroot(a)(0-1)<150>{l_2}
\istb{A}[l]
\istb{\neg A}[r]{SQ}
\endist
\istrootcntm(1)(a-1)[initial node]<180>{PM}+8mm..12mm+
\istb{x}[r]
\endist
\istroot(b)(1-1)<150>{l_2}
\istb{Y}[l]{x}[bl]
\istb{N}[r]
\endist
\istroot(c)(b-2){l_i}
\istb{VNC}[l]
\istb{\neg VNC}[r]{\ddots}[br]
\endist
\istroot(d)(c-1){l_i}
\istb{A}[l]{ne}[bl]
\istb{\neg A}[r]{\ddots}[br]
\endist
\end{istgame}
\end{document}

Here is another solution to use the package istgame, with which you can use \istcntm to draw a continuum of actions.

\documentclass{standalone}
\usepackage{istgame}
\begin{document}
\begin{istgame}[scale=2.5,font=\footnotesize]
\xtdistance{8mm}{20mm}
\istcntm(ctm0)+8mm..12mm+
\istroot(0)(ctm0)[initial node]{$PM$}+\cntmlevdist..\cntmlevdist+
\istb{p}[r]
\endist
\istroot(a)(0-1)<150>{$l_2$}
\istb{A}[l]
\istb{\neg A}[r]{SQ}
\endist
\istcntm(ctm1)(a-1)+8mm..12mm+
\istroot(1)(ctm1)[initial node]<180>{$PM$}+\cntmlevdist..\cntmlevdist+
\istb{x}[r]
\endist
\istroot(b)(1-1)<150>{$l_2$}
\istb{Y}[l]{x}[bl]
\istb{N}[r]
\endist
\istroot(c)(b-2){$l_i$}
\istb{VNC}[l]
\istb{\neg VNC}[r]{\ddots}[br]
\endist
\istroot(d)(c-1){$l_i$}
\istb{A}[l]{ne}[bl]
\istb{\neg A}[r]{\ddots}[br]
\endist
\end{istgame}
\end{document}