Mark Angle in 3D

I'd like to mark angles in a 3D-pstricks-graphic. I tried to use the solution seen in this question:

Right angle in 3D-pstricks

Unfortunately, it doesn't work. Here's my code:

\documentclass{standalone}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[ngerman]{babel}
\usepackage{pst-all}
\usepackage{pst-3dplot}

\begin{document}

\psset{coorType=2,Alpha=90}
\begin{pspicture}[showgrid=false](-1.5,-1.5)(5.5,3.1)
\pstThreeDLine[linewidth=0.5pt,linecolor=black,linestyle=dashed](2,0,0)(0,0,0)(0,0,3)
\pstThreeDLine[linewidth=0.5pt,linecolor=black,linestyle=dashed](0,0,0)(0,5,0)
\pstThreeDTriangle[fillstyle=solid,fillcolor=red!40,linewidth=0.2pt,linecolor=red,opacity=0.6](2,0,0)(0,0,1.5)(0,5,0)
\pstThreeDLine[linewidth=0.8pt,linecolor=black,linestyle=solid](2,0,0)(2,5,0)(0,5,0)(0,5,3)(2,5,3)(2,0,3)(2,0,0)
\pstThreeDLine[linewidth=0.8pt,linecolor=black,linestyle=solid](2,5,0)(2,5,3)
\pstThreeDLine[linewidth=0.8pt,linecolor=black,linestyle=solid](2,0,3)(0,0,3)(0,5,3)
\uput{0.1cm}[225](-1,-1){$A$}
\uput{0.1cm}[180](0,1.5){$B$}
\uput{0.1cm}[0](5,0){$C$}
\rput[c](1.5,-1.2){$a$}
\rput[l](4.6,-0.6){$b$}
\rput[l](5.1,1.5){$c$}
\ThreeDput[normal=7.5 3 10](0,0,1.5){
\psarc{-}(0,0){0.4}{0}{80}
}
\end{pspicture}

\end{document}


It should look like this:

If possible, the symbol of each angle should be put in the same plain as the triangle. Thank you very much for your help!

• That's a good question. What is disturbing me most is that the outcome depends on whether I compile with xelatex or with latex -> dvi -> ps -> pdf, see also this post. – user121799 Apr 22 '18 at 18:40

Use \pstThreeDEllipse for marking the angle:
 \pstThreeDEllipse[beginAngle=0,endAngle=90,

(0,0,1.5) is the origin (center) of the circle and (0.2,0,-0.15)(0,0.25,-0.075) the two radii of the ellipse (circle).