Custom \if command to check for multiple conditions

Question

I'm creating a document class for bachelors' and masters' theses at my faculty. It's almost ready and tuned to this year's official requirements. However, things may change in future: for example, the management may suddenly change the title page layout or do anything like this. So, I want to add version options to my class to be specified like in the following:

\documentclass[v2018]{physvsuThesis}

With the help of these options, I plan to retain backward compatibility while being able to incorporate new requirements on demand.

However, I don't know how to manage such conditionals in a convenient way. Using plain TeX's \newif along does not seem like a viable option. The only solution I can think of is to roll out my custom commands to implement conditional logic, like this:

\DeclareOption{v2018}{\setVersion{2018}}
\DeclareOption{v2019}{\setVersion{2019}}
...

\ifVersion{2018, 2019} % logical OR
  ...
\fi

How can I implement the \ifVersion command so it can check for multiple conditions and work even if nested?

Answer 1

A one liner in expl3:

\documentclass{article}
\usepackage{xparse}

\ExplSyntaxOn
% this assumes that \classversion contains the version

\NewDocumentCommand{\ifVersion}{mmO{}}
 {% #1 is a list of items of the form {year,...}
  % #2 is the code to execute in case of a match
  % #3 (optional) is the code to use in case of no match
  \str_if_in:nVTF { #1 } \classversion { #2 } { #3 }
 }
\prg_generate_conditional_variant:Nnn \str_if_in:nn { nV } { T, F, TF }
\ExplSyntaxOff

\def\classversion{2018} % emulate what the class does

\begin{document}

\ifVersion{2018}{Version 2018}[Not version 2018]

\ifVersion{2017,2018}{This is 2017 or 2018}

\ifVersion{2016}{Nothing} $\leftarrow$ nothing

\ifVersion{2016}{Nothing}[Not 2016]

\ifVersion{2016,2017}{Nothing} $\leftarrow$ nothing

\end{document}

Answer 2

A simple implementation using expl3 with \if ... \fi:

\documentclass{article}
\usepackage{expl3,xparse}
\ExplSyntaxOn
\str_new:N\g_my_version_str
\NewDocumentCommand\setVersion{ m }{
  \str_gset:Nn \g_my_version_str { #1 }
}
\NewDocumentCommand\ifVersion{ m }{
  \clist_if_in:nVTF { #1 } {\g_my_version_str} {\iftrue} {\iffalse}
}
\ExplSyntaxOff
\begin{document}
\setVersion{2018}
\ifVersion{2017, 2018}
+1\\
\fi
\ifVersion{2017, 2015}
+2\\
\fi
\end{document}

This leads to problems in nested conditionals because TeX does not see \ifVersion as a \if command, so the \else/\fi parsing gets out of sync in an unevaluated context.

Instead it is better to pass the conditional commands as arguments:

\documentclass{article}
\usepackage{expl3,xparse}
\ExplSyntaxOn
\str_new:N\g_my_version_str
\NewDocumentCommand\setVersion{ m }{
  \str_gset:Nn \g_my_version_str { #1 }
}
\NewDocumentCommand\ifVersion{ m }{
  \clist_if_in:nVTF { #1 } {\g_my_version_str}
}
\ExplSyntaxOff
\begin{document}
\setVersion{2018}
\ifVersion{2017, 2018}{+1}{Not +1}
\ifVersion{2017, 2015}{+2}{Not +2}
\end{document}

Answer 3

You can do that with no package:

\documentclass{article}

\makeatletter
\newcommand{\setVersion}[1]{\def\fire@version{#1}}

\setVersion{2018-06-08}

\newcommand{\ifVersion}[1]{\ifnum\numexpr#1>0
    \expandafter\@firstoftwo
  \else
    \expandafter\@secondoftwo
  \fi
}

\newcommand\IS[1]{%
  \if0\expandafter\pdfstrcmp\expandafter{\fire@version}{#1}%
    \expandafter1%
  \else
    \expandafter0%
  \fi}

\newcommand\ISNOT[1]{%
  \if0\expandafter\pdfstrcmp\expandafter{\fire@version}{#1}%
    \expandafter0%
  \else
    \expandafter1%
  \fi}

\newcommand\AND[2]{(#1*#2)}

\newcommand\OR[2]{(#1+#2-#1*#2)}

\newcommand\NOT[1]{(1-#1)}

\makeatother

\begin{document}

\ifVersion
{\AND{\OR{\OR{\IS{v1}}{\IS{v2}}}{\IS{2018-06-08}}}{\ISNOT{2017-05-11}}}
{YES}
{NO}
% YES

\ifVersion
{\OR{\OR{\OR{\IS{v1}}{\IS{v2}}}{\IS{2018-06-08}}}{\IS{2017-05-11}}}
{YES}
{NO}
% YES

\ifVersion
{\AND{\OR{\OR{\IS{v1}}{\IS{v2}}}{\IS{2018-06-08}}}{\IS{2017-05-11}}}
{YES}
{NO}
% NO

\end{document}

The above solution uses \pdfstrcmp because I didn't want to assume version numbers would be only numeric.

The above is nestable with no problem.

Now, for more convenient infix notations, you can use xintexpr which provides \xintifboolexpr as well as the functions bool() and togl(). Check the docs. This will allow you to combine (with bool()) TeX conditionals in arbitrarily complicated logic expressions.

Answer 4

Perhaps a bit overkill, but can be done with iterating. Using e.g. pgffor and xstring:

\documentclass{article}
\usepackage{xstring}
\usepackage{pgffor}
\newif\ifIsInList

% #1: haystack
% #2: needle
% #3: action if found in list
% #4: action if not found in list
\gdef\isin#1#2#3#4{
    \global\IsInListfalse%
    \def\needle{#2}%
    \def\haystack{#1}%
    \makeatletter\IfInteger{\needle}{}{\@latex@error{ISIN: Can't look for list item that is not numeric!}{}\bye\stop}\makeatother%
    \IfInteger{\haystack}{%
        \ifnum\haystack=\needle\relax%
            #3%
        \else%
            #4%
        \fi%
    }{%
        \foreach \pp in {#1}{%
                \ifnum\pp=\needle\relax%
                    \global\IsInListtrue%
                    #3%
                \fi%
            }%
        \ifIsInList\else%
            #4%
        \fi%
    }%
}
\begin{document}
%\isin{Comma Separated List}{Look for}{If found}{If not found}
\isin{2011,2012}{2011}{2011 is in the list!}{2011 is not in the list}%
\isin{2011,2012}{2013}{2013 is in the list!}{2013 is not in the list}
\end{document}

xstring is not strictly needed - just to catch the error if the first argument is an integer, and make sure that the second argument is an integer.