0

In the equation below, +Z_th,kp must stay aligned to the right end of the equal sign, but it seems that I cannot do this without beginning a new line and suppressing its tag. As a result, the numbering becomes aligned to the top as seen here:

enter image description here

How I want the tag to be is like this:

enter image description here

Note that I am using align environment because there is a long derivation and the = sign must stay aligned among all equations. Hence, the solution must maintain the = sign alignment in some fashion. My MWE:

\documentclass[11pt, a4paper]{IEEEtran}

\usepackage{amsmath}
\usepackage{amssymb, amsfonts}

\begin{document}


\begin{align}
\Delta{Z_{lm}} &=  - \frac{(Z_{lk} - Z_{lp})(Z_{km} - Z_{pm})} {Z_{th,kp}- j \frac{d}{y_{b}}}
\\
j \frac{d}{y_{b}} &= \frac{(Z_{lk} - Z_{lp})(Z_{km} - Z_{pm})}{\Delta{Z_{lm}}}
\label{eq:d_yb_find}
\\
&\hphantom{=} + Z_{th,kp}
\notag
\end{align}

\end{document}
0

enter image description here

\documentclass[11pt, a4paper]{IEEEtran}

\usepackage{amsmath}
\usepackage{amssymb, amsfonts}

\begin{document}


\begin{align}
\Delta{Z_{lm}} &=  - \frac{(Z_{lk} - Z_{lp})(Z_{km} - Z_{pm})} {Z_{th,kp}- j \frac{d}{y_{b}}}
\\
\begin{split}
j \frac{d}{y_{b}} &= \frac{(Z_{lk} - Z_{lp})(Z_{km} - Z_{pm})}{\Delta{Z_{lm}}}
\label{eq:d_yb_find}
\\
&\hphantom{=} + Z_{th,kp}
\end{split}
\end{align}

\end{document}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.