Tabularx: Multiple vertical top columns and multiple vertical bottom columns

Question

I have been trying for several hours to achieve the following appearance using tabularx with no success:

• Column 1: Aligned vertical top, horizontal right.
• Column 2: Aligned vertical top, horizontal left.
• Column 3: Aligned vertical top, horizontal left, expanding width (e.g. X).
• Columns 4,5,6: Aligned vertical bottom, horizontal right

I managed to get last three columns aligned vertically at bottom relative to the 'Long Text' column, but this had undesired effects on the first two column which are now also vertically aligned bottom. How can I align the first two columns vertically at the top while keeping the other columns as they are?

Table Source:

\begin{table}
\renewcommand{\tabularxcolumn}[1]{b{#1}}
\newcolumntype{R}{>{\raggedleft\arraybackslash}p{0.9cm}}
\begin{tabularx}{\textwidth}[ht]{|r|p{2.7cm}|X|R|R|R|}
\hline
\textbf{\texttt \#} &
\textbf{Info} &
\textbf{Long Text} &
{\raggedright \bfseries Col 1 \\(foo.)} &
{\raggedright \bfseries Col 2 \\(bar.)} &
{\raggedright \bfseries Col 3 \\(baz.)}
\\ \hline
1 & \raggedright One, \newline thing & \lipsum*[1] &
    1.11 &
    2.22 &
    3.33 \\ \hline

2 & \raggedright Some, \newline Thing & \lipsum*[1] &
    1.55 &
    3.66 &
    6.99 \\ \hline

\end{tabularx}
\caption{XXX}
\label{tab:xxx}
\end{table}

Table Appearance:

The red arrows show how cell content should move to achieve the desired result.

Update: Clarified the desired result.

Answer 1

I propose this dirty hack: using \multirow{-n} in the first two columns. n is approximately twice the number of lines in the next X cell.

\documentclass[10pt]{article}
\usepackage{geometry}
\usepackage{tabularx, makecell, multirow}
\usepackage{lipsum}

    \begin{document}

\begin{table}
\renewcommand{\tabularxcolumn}[1]{b{#1}}
\newcolumntype{R}{>{\raggedleft\arraybackslash}b{1cm}}
\begin{tabularx}{\textwidth}[ht]{|r|p{2.7cm}|X|R|R|R|}
\hline
\textbf{\texttt \#} &
\textbf{Info} &
\textbf{Long Text} &
{\raggedright \bfseries Col 1 \\(foo.)} &
{\raggedright \bfseries Col 2 \\(bar.)} &
{\raggedright \bfseries Col 3 \\(baz.)}
\\ \hline
\multirowcell{-41}{1 }& \multirow{-40}{=}{One, \\ thing} & \lipsum*[1] &
    1.11 &
    2.22 &
    3.33 \\ \hline

\multirowcell{-41}{2} & \multirow{-40}{=}{Some, \\ Thing} & \lipsum*[1] &
    1.55 &
    3.66 &
    6.99 \\ \hline

\end{tabularx}
\caption{XXX}
\label{tab:xxx}
\end{table}

\end{document} 

Answer 2

I'd use a simple table definition dividing every row into two and shifting up the second row with \\[...].

\documentclass[10pt]{article}
\usepackage{geometry}
\usepackage{tabularx, makecell, multirow}
\usepackage{array}
\renewcommand{\arraystretch}{1.3}
\usepackage{lipsum}

\begin{document}
\begin{table}\centering
\begin{tabular}{|p{.6em}|p{2.7em}|p{23em}|c|c|c|}
\hline
\textbf{\texttt \#} & \textbf{Info} & \textbf{Long Text} & \textbf{Col 1} &
    \textbf{Col 2} & \textbf{Col 3}\\[-4pt]
 & & & \textbf{(foo.)} & \textbf{(bar.)} & \textbf{(baz.)}\\ 
\hline
1& One, thing & \lipsum*[1] & & & \\[-3.5ex] 
\multicolumn{1}{c}{}&\multicolumn{1}{c}{} &\multicolumn{1}{c}{}  &
    \multicolumn{1}{c}{1.11} &
    \multicolumn{1}{c}{2.22} &
    \multicolumn{1}{c}{3.33} \\ 
\hline
2 & Some, Thing & \lipsum*[1] & & & \\[-3.54ex] 
\multicolumn{1}{c}{}&\multicolumn{1}{c}{} &\multicolumn{1}{c}{}  &
    \multicolumn{1}{c}{1.55} &
    \multicolumn{1}{c}{3.66} &
    \multicolumn{1}{c}{6.99} \\ 
\hline
\end{tabular}
\caption{XXX}\label{tab:xxx}
\end{table}
\end{document}