0
\documentclass{tudelft-report}
\usepackage[utf8]{inputenc}
\usepackage{algorithm,algorithmicx,algpseudocode}
\begin{algorithm}
\caption{cICA}\label{cICA}
\begin{algorithmic}[1]
\Procedure{cICA}{}\Comment{The procedure of cICA}
\State \textbf{Initialization} $b$\Comment{Initialize the parameters}
\begin{align*}
    \mu& = 1      \quad \lambda  = 1\\
    \gamma& = 1   \quad \eta  = 1\\
    threshold& = 0.00001 \quad flag =1\\
\end{align*}
\While{$r\not=0$}\Comment{stop the loop when the changed value of weighted 
vector is larger than threshold}
\State $\mu_{t} = max\{0,\mu_{t-1}+\gamma g(w_{t-1})\}$
\State $\lambda_{t} = \lambda_{t-1}+\gamma h(w_{t-1})$
\State $\Gamma_{1} = \overline{\rho}E\{zG'_{y}(y)\} - \frac{1}{2}\mu E\{zg'_{y}(y)\}-\lambda E\{zy\}$
\State $\Gamma_{2} = \overline{\rho}E\{G"_{y^{2}}(y)\} - \frac{1}{2}\mu E\{g"_{y^{2}}(y)\}-\lambda$
\If{$norm(w_{k} - w_{k-1}) < threshold$ }
 \State flag = 0;
\Else
\State flag = 1;
\EndIf
\EndWhile\label{euclidendwhile}
\State \textbf{return} $w$\Comment{The optimal weight vector $w$}
\EndProcedure
\end{algorithmic}
\end{algorithm}

enter image description here

When I was using the comment command in algorithmicx, there is always a bank square at the beginning of the text. Could anaynoe help me with this?

1

You can redefine the way algorithmicx's \Comment works using

\algrenewcommand\algorithmiccomment[1]{\hfill #1}

According to this answer, the default behavior of \Comment is to insert \hfill \(\triangleright\). The above redefines it to not render a symbol. You can alternatively use any other symbol.

When replacing the documentclass{tudeflt-report} with another documentclass, e.g. \documentclass{article}, the triangle is correctly rendered (instead of the box), so this might be an issue with the used documentclass.

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{algorithm,algorithmicx,algpseudocode}

\algrenewcommand\algorithmiccomment[1]{\hfill #1}

\begin{document}

\begin{algorithm}
\caption{cICA}\label{cICA}
\begin{algorithmic}[1]
\Procedure{cICA}{}\Comment{The procedure of cICA}
\State \textbf{Initialization} $b$  \Comment{Initialize the parameters}
\begin{align*}
    \mu& = 1      \quad \lambda  = 1\\
    \gamma& = 1   \quad \eta  = 1\\
    threshold& = 0.00001 \quad flag =1\\
\end{align*}
\While{$r\not=0$}\Comment{stop the loop when the changed value of weighted 
vector is larger than threshold}
\State $\mu_{t} = max\{0,\mu_{t-1}+\gamma g(w_{t-1})\}$
\State $\lambda_{t} = \lambda_{t-1}+\gamma h(w_{t-1})$
\State $\Gamma_{1} = \overline{\rho}E\{zG'_{y}(y)\} - \frac{1}{2}\mu E\{zg'_{y}(y)\}-\lambda E\{zy\}$
\State $\Gamma_{2} = \overline{\rho}E\{G"_{y^{2}}(y)\} - \frac{1}{2}\mu E\{g"_{y^{2}}(y)\}-\lambda$
\If{$norm(w_{k} - w_{k-1}) < threshold$ }
 \State flag = 0;
\Else
\State flag = 1;
\EndIf
\EndWhile\label{euclidendwhile}
\State \textbf{return} $w$\Comment{The optimal weight vector $w$}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\end{document}

Rendered LaTeX

| improve this answer | |
  • I'm glad I could help. Would you like to mark the answer as accepted? – chrisma Jul 24 '18 at 14:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.